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krek1111 [17]
3 years ago
6

Which formula can be used to calculate the horizontal displacement of a horizontally launched projectile?

Physics
1 answer:
Jet001 [13]3 years ago
7 0
I think D x=vxt because it's equation finding change of x (displacement) and using time
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Consider the following geometric solids.
Bad White [126]

Before answering this question, first we have to understand the effect of ratio of surface area to volume on the rate of diffusion.

The rate of diffusion for a body having larger surface area as compared to the ratio of surface area to volume will be more than a body having less surface area. Mathematically it can written as-

                           V∝ R            [ where v is the rate of diffusion and r is the ratio of surface area to volume]

As per the question,the ratio of surface area to volume for a sphere is given 0.08m^{-1}

The surface area to volume ratio for right circular cylinder is given 2.1m^{-1}

Hence, it is obvious that the ratio is more for right circular cylinder.As the rate diffusion is directly proportional to the surface area to volume ratio,hence rate of diffusion will be more for right circular cylinder.

Hence the correct option is B. The rate of diffusion would be faster for the right cylinder.


5 0
3 years ago
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Light has a frequency of about 6 x1014 Hz.
abruzzese [7]

Answer:

The visible light frequency is 400 THz to 700 THz, approximately. A THz is a Terahertz, which is a unit of frequency equal to one trillion Hertz.

4 0
2 years ago
A certain race track is four and a half kilometers long. The winning driver in the race drove his car around the track TWICE in
Vika [28.1K]

he drove 3 kilometers every minute

4 0
3 years ago
A heavy solid disk rotating freely and slowed only by friction applied at its outer edge takes 120 seconds to come to a stop.
alisha [4.7K]

Answer:

The time is 16 min.

Explanation:

Given that,

Time = 120 sec

We need to calculate the moment of inertia

Using formula of moment of inertia

I=\dfrac{1}{2}MR^2

If the disk had twice the radius and twice the mass

The new moment of inertia

I'=\dfrac{1}{2}\times2M\times(2R)^2

I'=8I

We know,

The torque is

\tau=F\times R

We need to calculate the initial rotation acceleration

Using formula of acceleration

\alpha=\dfrac{\tau}{I}

Put the value in to the formula

\alpha=\dfrac{F\times R}{\dfrac{1}{2}MR^2}

\alpha=\dfrac{2F}{MR}

We need to calculate the new rotation acceleration

Using formula of acceleration

\alpha'=\dfrac{\tau}{I'}

Put the value in to the formula

\alpha=\dfrac{F\times R}{8\times\dfrac{1}{2}MR^2}

\alpha=\dfrac{2F}{8MR}

\alpha=\dfrac{\alpha}{8}

Rotation speed is same.

We need to calculate the time

Using formula angular velocity

\Omega=\omega'

\alpha\time t=\alpha'\times t'

Put the value into the formula

\alpha\times120=\dfrac{\alpha}{8}\times t'

t'=960\ sec

t'=16\ min

Hence, The time is 16 min.

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3 years ago
When positively charged particles were radiated onto a gold atom, a few of the particles bounced back. Which of the following ca
ratelena [41]

Positively charged protons in the nucleus of the gold atom .... rutherford scattering ???


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3 years ago
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