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krek1111 [17]
3 years ago
6

Which formula can be used to calculate the horizontal displacement of a horizontally launched projectile?

Physics
1 answer:
Jet001 [13]3 years ago
7 0
I think D x=vxt because it's equation finding change of x (displacement) and using time
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Which statement best describes an electric current?
goldenfox [79]

Answer:

its B

Explanation:

the movement of charged particles in a conductor

7 0
3 years ago
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Surrounding a magnet is a magnetic field. Surrounding an electron is an electric field. Surrounding Earth is
trasher [3.6K]

Answer: B. A gravitational field

Explanation:

Surrounding earth is gravitational field. Gravitational field is a region of space were gravitational force can be felt and gravitational force is the gravitational pull on the surface of the earth. The presence of this gravity is what allow us to be able to walk freely without falling. It also make us jump up and be able to land back on the ground. Assuming there are no force of gravity in the surface of the earth, there won't be any possibility of landing back on the ground after jumping.

6 0
3 years ago
Which human activity causes the most erosion?
Ksivusya [100]

Answer:

B

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3 0
3 years ago
While brayden is traveling along a straight interstate highway, he notices that the mile marker reads 260. Brayden travels until
Yuki888 [10]

Answer:

<em>displacement = -85 miles</em>

Explanation:

<u>Displacement </u>

It's a magnitude used to measure the linear space between two points. It's computed as the subtraction of the final position minus the initial position which results in a vector. Notice the displacement only depends on the initial and final positions and not on the path the object has traveled.

Brayden starts to measure his position when the mile marker reads 260. Then he travels to the 150-mile marker and goes back to the 175-mile marker, his final position. As mentioned, the displacement only depends on the relative positions, so

displacement = 175 - 260 = -85 miles

5 0
4 years ago
Two children are riding on the edge of a merry-go-round that has a mass of 100.kg and radius of 1.60m and is rotating at 20.0rpm
Gre4nikov [31]

Here since both children and merry go round is our system and there is no torque acting on this system

So we will use angular momentum conservation in this

I_1\omega_1 = I_2\omega_2

now here we have

I_1 = \frac{MR^2}{2} + m_1R^2 + m_2R^2

I_1 = \frac{100(1.60)^2}{2} + (22 + 28)(1.60)^2

I_1 = 256

Now when children come to the position of half radius

then we will have

I_2 = \frac{MR^2}{2} + m_1(\frac{R}{2})^2 + m_2(\frac{R}{2})^2

I_2 = \frac{100(1.6)^2}{2} + (28 + 22)(0.8)^2

I_2 = 160

now from above equation we have

256 (20.0 rpm) = 160(\omega_2)

\omega_2 = 32 rpm

8 0
3 years ago
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