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Alexandra [31]
3 years ago
10

________________________involves connecting a voltmeter set to read DC volts to the suspected high-resistance cable ends and cra

nking the engine.
Physics
1 answer:
AnnyKZ [126]3 years ago
4 0

Answer:

Voltage Drop Testing

Explanation:

The motives behind conducting Voltage Drop Testing is to recognize or identify the presence of unwanted resistance in the wire. or any other electrical appliance.  The appliance used to calculate the voltage drop is digital volt ohmmeters.  

voltage drop is the amount of loss of voltage due to resistance when electric current flow through the circuit. Thus measuring the voltage drop in respect to the amount of current flow, resistance can be measured.

You might be interested in
A wire carrying a 29.0 A current passes between the poles of a strong magnet such that the wire is perpendicular to the magnet's
Dmitrij [34]

Answer:

2.59 T

Explanation:

Parameters given:

Current flowing through the wire, I = 29 A

Angle between the magnetic field and wire, θ = 90°

Magnetic force, F = 2.25 N

Length of wire, L = 3 cm = 0.03 m

The magnetic force, F, is related to the magnetic field, B, by the equation below:

F = I * L * B * sinθ

Inputting the given parameters:

2.25 = 29 * 0.03 * B * sin90

2.25 = 0.87 * B

=> B = 2.25/0.87

B = 2.59 T

The magnetic field strength between the poles is 2.59 T

4 0
3 years ago
Why must objects be cooled before their mass is determined on a sensitive balance?
zubka84 [21]
Objects should be cooled before their mass is determined on a sensitive balance because it could damage the balance. Also, because it would give you wrong reading of the mass. Hot objects would warm the air around it. A warm air would expand and would produce convection as it rises causing to give the object a mass that is less than the actual. Another reason would be it would cause instability in the readings, the mass would fluctuate every now and then due to the convection currents around the object. It is always recommended to weigh the masses of objects that are in room temperature.
5 0
3 years ago
D
inysia [295]

<u>Hello and Good Morning/Afternoon</u>:

<em>Original Question: C₂H₅OH + __O₂ → __CO₂ + __ H₂O</em>

<u>To balance this equation</u>:

⇒ must ensure that there is an equal number of elements on both sides of the equation at all times

<u>Let's start balancing:</u>

  • On the left side of the equation, there are 2 carbon molecule

              ⇒ but only so far one on the right side

         C<em>₂H₅OH + __O₂ →  2CO₂ + __ H₂O</em>

  • On the left side of the equation, there are 6 hydrogen molecules

               ⇒ but only so far two on the right side

         C<em>₂H₅OH + __O₂ →  2CO₂ + 3H₂O</em>

  • On the right side of the equation, there are 7 oxygen molecules

                ⇒ but only so far three on the left side

         C<em>₂H₅OH + 3O₂ →  2CO₂ + 3H₂O</em>

<u>Let's check and make sure we got the answer:</u>

                           C<em>₂H₅OH + 3O₂ →  2CO₂ + 3H₂O</em>

<em>                 2 Carbon                ⇔                    2 Carbon</em>

<em>                 6 Hydrogen            ⇔                   6 Hydrogen</em>

<em>                 7 Oxygen                ⇔                   7 oxygen</em>

<u>Thefore the coefficients in order are</u>:

  ⇒ 1, 3, 2, 3

<u>Answer: 1,3,2,3</u>

Hope that helps!

#LearnwithBrainly<em>                      </em>

5 0
2 years ago
A circular wire loop of radius 15.0 cm carries a current of 2.60
Korolek [52]
Part (a): Magnetic dipole moment

Magnetic dipole moment = IA, I = Current, A = Area of the loop
Then,
Magnetic dipole moment = 2.6*π*0.15^2 = 0.184 Am^2

Part (b): Torque acting on the loop
T = IAB SinФ, where B = Magnetic field, Ф = Angle
Then,
T = Magnetic dipole moment*B*SinФ = 0.184*12*Sin 41 = 1.447 Nm
5 0
3 years ago
What is the magnitude of the magnetic field at a point midway between them if the top one carries a current of 19.5 A and the bo
Phantasy [73]

Answer:

The magnetic field will be \large{\dfrac{1.4 \times 10^{-4}}{d}} T, '2d' being the distance the wires.

Explanation:

From Biot-Savart's law, the magnetic field (\large{\overrightarrow{B}}) at a distance 'r' due to a current carrying conductor carrying current 'I' is given by

\large{\overrightarrow{B} = \dfrac{\mu_{0}I}{4 \pi}} \int \dfrac{\overrightarrow{dl} \times \hat{r}}{r^{2}}}

where '\overrightarrow{dl}' is an elemental length along the direction of the current flow through the conductor.

Using this law, the magnetic field due to straight current carrying conductor having current 'I', at a distance 'd' is given by

\large{\overrightarrow{B}} = \dfrac{\mu_{0}I}{2 \pi d}

According to the figure if 'I_{t}' be the current carried by the top wire, 'I_{b}' be the current carried by the bottom wire and '2d' be the distance between them, then the direction of the magnetic field at 'P', which is midway between them, will be perpendicular towards the plane of the screen, shown by the \bigotimes symbol and that due to the bottom wire at 'P' will be perpendicular away from the plane of the screen, shown by \bigodot symbol.

Given \large{I_{t} = 19.5 A} and \large{I_{B} = 12.5 A}

Therefore, the magnetic field (\large{B_{t}}) at 'P' due to the top wire

B_{t} = \dfrac{\mu_{0}I_{t}}{2 \pi d}

and the magnetic field (\large{B_{b}}) at 'P' due to the bottom wire

B_{b} = \dfrac{\mu_{0}I_{b}}{2 \pi d}

Therefore taking the value of \mu_{0} = 4\pi \times 10^{-7} the net magnetic field (\large{B_{M}}) at the midway between the wires will be

\large{B_{M} = \dfrac{4 \pi \times 10^{-7}}{2 \pi d} (I_{t} - I_{b}) = \dfrac{2 \times 10^{-7}}{d} = \dfrac{41.4 \times 10 ^{-4}}{d}} T

5 0
3 years ago
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