Question

Which expression has the same dimensions as an expression yielding a value for acceleration (m/s2)? (delta v has units of m/s.) Group of answer choices delta v/(delta t)^2 (delta v)^2/delta y (delta v)^2/delta t delta v/(delta y)^2

Answer 1

Answer:

Option (3).

Explanation:

The expression for acceleration of an object is given by :

$a=\dfrac{v-u}{t}$

(v-u) = the change in velocity and t is time taken

We need to write the option that has the ame dimensions as an expression yielding a value for acceleration (m/s²).

Option (1).

$\dfrac{\delta v}{(\delta t)^2}=\dfrac{m/s}{s^2}=m/s^3$

Option (2),

$\dfrac{(\delta v)^2}{\delta t}=\dfrac{m^2/s^2}{s^2}=m^2/s^4$

Option (3),

$\dfrac{(\delta v)^2}{\delta t}=\dfrac{m/s}{s}=m/s^2$

Hence, option (3) is same as the value of acceleration.