Answer:
pressure = density x g x height
= 1000 x 10 x 6 Pascal
=60000 Pascal
OR 60 kP
Answer: 0.087 inches
Explanation:
This problem can be solved applying the <u>Rule of three</u>, which is a mathematical rule to find out an amount that is with another quantity given in the same relation as other two also known.
In this sense, the actual diameter of the Sun is 1,391,020 km and the actual diameter of the Earth is 12,742 km.
Now, applying the <u>Rule of three:</u>
<u />
Sun 1,391,020 km ------ 9.5 inches
Earth 12,742 km --------- ? inches

Therefore:
If the sun is scaled down to 9.5 inches in diameter, the earth would be about <u>0.087 inches </u>in diameter.
SI unit for mas is Kg and the SI unit of weight N for newton
The answer is elliptical orbits. Here is are my reason for thinking it is what I know it is. All planets move in elliptical orbits, with the sun at one focus. This is one of Kepler's laws. The elliptical shape of the orbit is a result of the inverse square force of gravity. The eccentricity of the ellipse is greatly exaggerated here.