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3 years ago

Select the correct answer.

Chemistry

1 answer:

erastova [34]3 years ago

3 0

Scientific law

Explanation:

A scientific law is a term that refers to a fact that naturally occurs in the universe.

Scientific laws are natural laws and they hold true.

Scientific law is a well tested idea that holds through for a range of natural events.
Scientific theories are explanations of phenomenons drawn from series of tests.

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_Na+ Cl2 - -> _NaCl A 2,4 B 1,2 C 3,3 D 2,2

Natali [406]

Answer:

D 2,2

Explanation:

We can see that there are 2 chlorines on the reactant side so there has to be a 2 on the product side

Now we have Na + Cl2 --> 2NaCl

The problem now is that there are 2 sodiums on the product side so add a 2 to the Na on the reactant side

2Na + Cl2 --> 2NaCl

Now it's balanced!

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2 years ago

Which describes a property of all elements?

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Is Benzylamine soluble in water?

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3 years ago

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Calculate the molarity of a sugar solution if 4 liters of the solution contains 12 moles of sugar.

castortr0y [4]

Answer:

Explanation:

Molarity is one of the measures of the molar concentration of a solution, which can be calculated by using the formula below:

Molarity = number of moles ÷ volume

From the information given in this question, 4 liters of a solution contains 12 moles of sugar. This means that n = 12mol and V = 4L

Molarity = n/V

Molarity = 12/4

Molarity = 3

Hence, the molarity of the sugar solution is 3mol/L or 3M

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2 years ago

Formaldehyde is a carcinogenic volatile organic compound with a permissible exposure level of 0.75 ppm. At this level, how many

Flauer [41]

Answer : The amount of formaldehyde permissible are, $5.4\times 10^{-6}g$

Explanation : Given,

Density of air = $1.2kg/m^3=1.2g/L$ $(1kg/m^3=1g/L)$

First we have to calculate the mass of air.

$\text{Mass of air}=\text{Density of air}\times \text{Volume of air}$

$\text{Mass of air}=1.2g/L\times 6.0L$

$\text{Mass of air}=7.2g$

Now we have to calculate the amount of formaldehyde.

Permissible exposure level of formaldehyde = 0.75 ppm = $\frac{0.75g\text{ of formaldehyde}}{10^6g\text{ of air}}$

Amount of formaldehyde in 7.2 g of formaldehyde = $7.2g\times \frac{0.75g\text{ of formaldehyde}}{10^6g\text{ of air}}$

Amount of formaldehyde in 7.2 g of formaldehyde = $5.4\times 10^{-6}g$

Thus, the amount of formaldehyde permissible are, $5.4\times 10^{-6}g$

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3 years ago