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Ugo [173]
3 years ago
13

Which oh these statements describes a chemical property?

Chemistry
1 answer:
Gelneren [198K]3 years ago
3 0

Iron rusts when exposed to air → chemical property

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1. How does protein substance in animal hide or skin be preserved from bacterial infection during tanning?
anyanavicka [17]

Answer:

1. By being cured

2. To remove the silica impurities from haemetite

3. The cathode will be bronze while the anode will be the silver

4. i) Wastes from industrial processes

ii) Waste waters and sewage

iii) Dumping of wastes into water bodies

5) Three methods to reduce air pollution includes

i) Promote the use of recycled of materials

ii) Promote and use renewable sources of energy

iii) Limit activities that involve the burning of fuels such as encouraging the use of mass transit buses, preventing the occurrence of fires in forests

Explanation:

1. In order to preserve the proteins in the hides of animal skin from putrefaction they are cured with salt to remove by, osmotic pressure difference,  the water content present in the animal hide

2. To remove the silica impurities from haemetite

The calcium oxide obtained from the decomposition of calcium carbonate undergoes a chemical reaction with the sand impurities in the mineral, haematite, to form calcium silicate or s l a g

3. Electroplating involves charging the metal to be electroplated negatively that is making it the cathode and placing it in an electrolytic cell that has a solution of the metal ions containing the metal salts

Therefore, the bronze medal to be plated with silver will be made the cathode while the silver from which we obtain the silver ions will be made the anode

4. Three causes of water pollution includes

Wastes from industrial processes

Waste waters and sewage

Dumping of wastes into water bodies

5.  The major causes of air pollution are the oxides produced from the combustion of fossil fuels such as sulfur dioxide, carbon dioxide, carbon monoxide as well as chemical gases from industrial processes.

8 0
3 years ago
What is the density of an object with a volume of 12 mL and a mass of 38g?
Andreas93 [3]

Answer:

Hi im an online tutor and I can assist you with all your assignments. we have professionals in all fields. Check out our website https://toplivewriters.com

Explanation:

5 0
2 years ago
A gas has a volume of 4 L at a temperature of -33°C. if the temperature is increased to 27°C in the pressure remains constant wh
vitfil [10]

Answer:

5L

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

4 0
3 years ago
What is the empirical formula of the compound whose molecular formula is P4O10
Pepsi [2]
The empirical formula is the lowest reduced ration of the atoms present. In this case, it is P2O5
7 0
3 years ago
Read 2 more answers
In reality, a hydrate of iron(III) nitrate had to be used, not the anhydrous salt. As you may guess, some of the hydrate’s mass
liq [111]

<u>Answer:</u> The mass of nonahydrate iron (III) nitrate is 16.2 g

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of Fe(NO_3)_3 = 0.0020 M

Volume of solution = 2 L

Putting values in above equation, we get:

0.0200M=\frac{\text{Moles of }Fe(NO_3)_3}{2L}\\\\\text{Moles of }Fe(NO_3)_3=(0.0200mol/L\times 2L)=0.04mol

The chemical equation for the decomposition of hydrated iron (III) nitrate follows:

Fe(NO_3)_3.9H_2O\rightarrow Fe(NO_3)_3+9H_2O

By Stoichiometry of the reaction:

1 mole of iron (III) nitrate is produced from 1 mole of hydrated iron (III) nitrate

So, 0.04 moles of iron (III) nitrate will be produced from = \frac{1}{1}\times 0.04=0.04mol of hydrated iron (III) nitrate

To calculate the mass from given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of nonahydrate iron (III) nitrate = 404.0 g/mol

Moles of nonahydrate iron (III) nitrate = 0.04 moles

Putting values in above equation, we get:

0.04mol=\frac{\text{Mass of nonahydrate iron (III) nitrate}}{404.0g/mol}\\\\\text{Mass of nonahydrate iron (III) nitrate}=(0.04mol\times 404.0g/mol)=16.2g

Hence, the mass of nonahydrate iron (III) nitrate is 16.2 g

7 0
2 years ago
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