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3 years ago

Why does the rider continue to go the same height on the ramp every time and would continue to do that forever?

1 answer:

3 0

It’s called conservation of energy. The system (the rider) can’t randomly gain energy without something else giving it energy because energy can’t be created or destroyed, only transferred. The pendulum example is beyond popular and you see physics professors doing it all the time. I think your teacher wants you to say it’ll continue forever, but I don’t think it will. The system will most likely lose energy to its surroundings. And there’s things like air resistance which will, overtime, slow it down. So no, it won’t go on forever

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The motion of an electron is given by x(t)=pt3+qt2+r, with p = -2.3 m/s^3 ,q = +1.5 m/s^2 , and r = +9.0 m.A) Determine its velo

alexandr402 [8]

Answer:

$v(0)=0\\v(1)=-3.9\ m/s\\v(2)=-21.6\ m/s\\v(3)=-53.1\ m/s$

Explanation:

<u>Instant Velocity </u>

Given the position as a function of time x(t), the instant velocity is the derivative of the function:

$v(t)=x'(t)$

We are given the position as

$x(t)=-2.3t^3+1.5t^2+9$

The derivative of x is

$v(t)=x'(t)=-6.9t^2+3.0t$

A) Let's compute v(0)

$v(0)=-6.9(0)^2+3.0(0)=0$

$v(1)=-6.9(1)^2+3.0(1)$

$v(1)=-3.9\ m/s$

$v(2)=-6.9(2)^2+3.0(2)$

$v(2)=-21.6\ m/s$

$v(3)=-6.9(3)^2+3.0(3)$

$v(3)=-53.1\ m/s$

4 0

3 years ago

What is the tail of a comet made of

ycow [4]

The tail consists of gas and dust that can extend hundreds of millions of kilometers away from the coma. Most comets actually have 2 tails: a plasma tail made of ionizedgas, and a dust tail made of small solidparticles. Comet tails point away from the Sun.

3 0

3 years ago

At the presentation ceremony, a championship bowler is presented a 1.64-kg trophy which he holds at arm's length, a distance of

solong [7]

To solve the problem it is necessary to take into account the concepts of the kinetic equations for the description of the torque at the rate of force and distance.

By definition the torque is given by,

$\tau = F*d$

where,

$F= Force$

$d = Distance$

For the problem in question the mass of the trophy is 1.64Kg and the distance of the tropeo to the board (the shoulder) is 0.655m

PART A) For part A, the torque with the given mass and the stipulated torque in the horizontal plane must be calculated as well,

$\tau = F*d$

For Newton's second law

$\tau = mg*d$

$\tau = 1.64*9.81*0.655$

$\tau = 10.5Nm$

PART B) For part B there is an angle of 26 degrees with respect to the horizontal, therefore to know the net torque it is necessary to know the horizontal component to the formed angle, that is,

$\tau = F*dcos\theta$

$\tau = mgdcos\theta$

$\tau = 1.64*9.81*0.655*cos26$

$\tau = 9.471Nm$

3 0

3 years ago

AEROSPACE On the Moon, a falling object falls just 2.65 feet in the first second after being dropped. Each second it falls 5.3 f

aniked [119]

Answer:

d = 265 ft

Therefore, an object fall 265 ft in the first ten seconds after being dropped

Explanation:

This scenario can be represented by an arithmetic progression AP.

nth term = a + nd

Where a is the first term given as 2.63 ft.

d is the common difference and is given as 5.3ft.

n is the particular second/time.

To calculate how far the object would fall in the first 10 seconds, we can derive it using the sum of an AP.

d = nth sum = (n/2)(2a+(n-1)d)

Where n = 10 seconds

a = 2.65 ft

d = 5.3 ft

Substituting the values we have;

d = (10/2)(2×2.65 + (10-1)5.3)

d = 265 ft

Therefore, an object fall 265 ft in the first ten seconds after being dropped

4 0

3 years ago

Read 2 more answers

How is reflection of light used in research

mel-nik [20]

In order to read the publications of his peers, or read his own notes of the work
that he did on the previous day, or find his coffee mug on his desk in the lab, the
research scientist must arrange to have each of them illuminated with visible
wavelengths of light, and then he must catch the light reflected from each of them
with his eyes.

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3 years ago