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2 years ago

The gcf of any two odd numbers is always odd

Mathematics

1 answer:

AleksAgata [21]2 years ago

5 0

your answer is correct

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7th grade math

Elza [17]

Answer:

1. b and g 2.a end e 3. d and f 4. g and h

Step-by-step explanation:

4 0

2 years ago

What is the slope of the line described 16x = 4y + 1

Dvinal [7]

Answer: The slope is 4x.

Step-by-step explanation: First, subtract 4y from both sides to get 16x-4y=1. Next, subtract 16x from both sides to get -4y=-16x+1. Finally, divide all terms by -4 to get y=4x-0.25. The slope is represented by 4x.

4 0

2 years ago

Khan academy<br><br>will mark.

german

Given:

$\theta_1$ is located in IV Quadrant.

$\sin (\theta_1)=-\dfrac{24}{25}$

To find:

The value of $\cos \theta_1$ .

Solution:

We have,

$\sin (\theta_1)=-\dfrac{24}{25}$

We know that,

$\sin^2 \theta+\cos^2\theta=1$

So,

$\sin^2 (\theta_1)+\cos^2(\theta_1)=1$

$\left(-\dfrac{24}{25}\right)^2+\cos^2(\theta_1)=1$

$\cos^2(\theta_1)=1-\dfrac{576}{625}$

$\cos^2(\theta_1)=\dfrac{625-576}{625}$

Taking square root on both sides, we get

$\cos (\theta_1)=\pm \sqrt{\dfrac{49}{625}}$

$\cos (\theta_1)=\pm \dfrac{7}{25}$

$\theta_1$ is located in IV Quadrant. In IV Quadrant the value of cos is positive. So,

$\cos (\theta_1)=\dfrac{7}{25}$

Therefore, $\cos (\theta_1)=\dfrac{7}{25}$ .

8 0

3 years ago

Construct a 2x2 matrix whose element are given by i+j

musickatia [10]

9514 1404 393

Answer:

see below

Step-by-step explanation:

Assuming i and j refer to the row and column of a given element, that matrix would be ...

$\left[\begin{array}{cc}2&3\\3&4\end{array}\right]$

Rows are numbered top down, starting with 1. Columns are numbered left-to-right, starting with 1. The upper left element is in row 1, column 1, so has a value here of 1+1 = 2. Each number is one more than the one to its left. Each number is 1 more than the one above it.

5 0

2 years ago

What is the number of possible permutations of 6 objects taken 3 at a time?

Nadya [2.5K]

Answer:

120

Step-by-step explanation:

The formula for permutations is n!/(n-r)!.

6=n and 3=r, and if you plug those numbers in you would get 120

6 0

2 years ago