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2 years ago

i'm really struggling how to solve this. It would help if i knew what i was doing but sadly, i don't.

2 answers:

8 0

Look if your struggling what with ever it is you can chat with me i can help you with what ever it is im in the 11th grade and im taking ap calculus if you need help with school i can help you if its personal ive gone through so many things im pretty sure i can still help you

olga2289 [7]2 years ago

5 0

What do u need?????
we need to see somethin

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Math problem+Zoey, a Gelada Baboon, is tied to one of the outside corners of a regular hexagon-shaped research facility, where h

dexar [7]

Answer

The monkey will be able to cover an area of 22.86 meters which is equivalent to two sides and half of the building.

Step-by-step explanation:

The length of the monkeys rope = 75 feet long

Each side of the hexagon shaped facility = 30 feet

Note that, 1 feet = 0.3048 m

if we convert 30 feet to Meter, we have,

30 × 0.3048 = 9.144

Therefore, 30 + 30 +15 = 75 which is equivalent to the two side and half side of the hexagon shaped building

75 feet × 0.304 meter = 22.86 meters.

So the total area the monkey will be able to cover will be

= 22.86 Meters which is equivalent to two sides and half of the hexagon shape building.

8 0

2 years ago

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

3 years ago

What is the product of -6x3y5 and -4y2? A. -24x3y7 B. -24x3y10 C. 24x3y7 D. 24x3y10

Leto [7]

Answer:

Step-by-step explanation:

So we have the product of:

$(-6x^3y^5)\cdot(-4y^2)$

Multiply. Combine like terms:

$=(-6\cdot -4)(x^3)(y^5\cdot y^2)$

The first term is 24.

The second term stays as it is.

The third term will equate to y^7. Recall how to multiply exponents. The base stays constant and you add the exponents. Thus:

$=24x^3y^7$

Our answer is C.

And we're done!

5 0

2 years ago

Determine the sign of cos pi/3 without using a calculator.

andre [41]

Pi/3 is in the first quadrant, and all trigonometric functions are positive in the first quadrant,
Therefore, cos pi/3 is positive.

8 0

3 years ago

Solve for x and y in the parallelogram

Lubov Fominskaja [6]

Answer:

x=3

y=6

Step-by-step explanation:

Hope this helps! :)

4 0

3 years ago