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77julia77 [94]
2 years ago
11

Help plssss no linkkkkk

Chemistry
2 answers:
pashok25 [27]2 years ago
8 0

Answer:

1 no. herbivore ....... 2 no. exception......3 no. diameter........4 no. heart........ 5 no. catastrophe...... 6 no. develop...... mark me brainliest plzzzz

stepladder [879]2 years ago
3 0

Answer:

1. Herbivore 2. Expectation 3. Diameter 4. Heart 5. Catastrophe 6. Develop

Explanation:

:)

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THE RIGHT ANSWER WILL RECIEVE A BRAINLEST AND POINTS AND THANXS!!!
PSYCHO15rus [73]
1 - Chemistry is a branch of science focusing on elements, reactions, and chemicals.

2 - We study chemistry to learn more about these chemicals and elements and to discover new chemicals as well as to answer questions in life about reactions.

3 - Chemistry relates to our life in various ways, from the chemicals we inhale to the basic reactions in cooking and baking.

4 - The main branches of Chemistry are Physical, analytical, biochemistry, organic and inorganic chemistry.

Hope this helps!
3 0
3 years ago
The volume (in L) that would be occupied by 5.00 mols of 02 at STP is
crimeas [40]

Answer : The volume of oxygen at STP is 112.0665 L

Solution : Given,

The number of moles of O_2 = 5 moles

At STP, the temperature is 273 K and pressure is 1 atm.

Using ideal gas law equation :

PV=nRT

where,

P = pressure of gas

V = volume of gas

n = the number of moles

T = temperature of gas

R = gas constant = 0.0821 L atm/mole K   (Given)

By rearranging the above ideal gas law equation, we get

V=\frac{nRT}{P}

Now put all the given values in this expression, we get the value of volume.

V=\frac{(5moles)\times (0.0821Latm/moleK)\times (273K)}{1atm}=112.0665L

Therefore, the volume of oxygen at STP is 112.0665 L

3 0
3 years ago
The following reaction has an activation energy of 262 kJ/mol.
Hitman42 [59]

Answer: i really       dont know srry

Explanation:

4 0
3 years ago
How would you prepare 10 ml of a 0.25% m/v hcl solution if 1% m/v hcl was available? how much 1% m/v hcl is needed? how much dis
Fed [463]

To solve this we use the equation, 

M1V1 = M2V2

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

M1V1 = M2V2

1% x V1 = 0.25% x 10 mL

V1 =2.5 mL

Therefore, you will need to have 2.5 mL of the 1% HCl solution and 7.5 mL of distilled water. In mixing the two liquids, you should remember that the order of mixing would be acid to water. So, you use a 10 mL volumetric flask . Put small amount of distilled water and add the 2.5 mL of HCl solution. Lastly, dilute with distilled water up to the 10 mL mark.

8 0
3 years ago
Select the fastest way to differentiate between the organic and aqueous layers of an extraction.a. Hold a white piece of paper b
valentinak56 [21]

Answer:

b. Add a few drops of one of the layers to a test tube containing 1 mL of water. Shake the test tube to determine the solubility of the layer in water

Explanation:

Option a is not true, it depends on the compound being extracted.

Option c is not true, although most of the solvents used in extractions have lower boiling point than water there are exceptions, for example toluene.

Option  d is not true. Again most of the solvents used in extractions are less dense than water, there are many exceptions, for example chloroform, so for equal volumes the chloroform layer will weigh more.

Option b. is the correct one.

One will test the  miscibility of the layer in water. If it inmiscible then one would know is the organic layer. If it is the aqueous layer then it will completely be miscible.

6 0
3 years ago
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