11/4% = (11/4)/100 = 11/400 = 0.0275;
1/4 = 0.2500;
1/80 = 0.0125;
We observe that 0.0125 < 0.0275 and 0.0114 < 0.0275 and 0.2500 > 0.0275 and 0.12500 > 0.0275;
The answers are c. and d.
D.) Dependent variable is "<span>instantaneous velocity" as it gives information of velocity at every second
Hope this helps!</span>
Move all the x terms to one side and solve for x. 15x-10x=21-6 : 5x/5=15/5 : x=3
Using Gauss's method
Total number of terms = [15-(-129)]/4+1=36+1=37
Add
S=15+11+7+....-125-129
S=-129-125-...+7+11+15
--------------------------------
2S=-114-114-114...(37 times)
=>
sum=S=(1/2)*(-114)*37=-2109
Using AP, T(n)=15+11+7+....-129
T(n)=19-4n => T(1)=15, T(37)=-129
S(n)=(1/2)(37)(T(1)+T(37)=(1/2)37(15-129)=2109
I think maybe 3) would make the most sense because she wants a random sample of students and the other options are specific on the type of students.
