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The appropriate response is the fourth one. The announcement is valid about this condition beneath is in spite of the fact that it is unequal, it can be adjusted by specifically utilizing observer particles.
I hope the answer will help you.
Answer:
6.25 g of Carbon is in Excess
Explanation:
The balance chemical equation is as follow:
C + O₂ → CO₂
Step 1: Calculate Moles of O₂ as:
Moles = Mass / M/Mass
Moles = 50 g / 32 g/mol
Moles = 1.562 mol of O₂
Step 2: Calculate Moles of C as;
Moles = 25 g / 12 g/mol
Moles = 2.08 mol
Step 3: Calculate the Limiting reagent:
According to equation,
1 moles of O₂ reacted with = 1 mole of C
So,
1.562 moles of O₂ will react with = X moles of C
Solving for X,
X = 1 mol × 1.562 mol / 1 mol
X = 1.562 mol of C
While we are provided with 2.08 mol of C. Means C is in excess.
Step 4: Calculate amount of Excess C as;
Excess Moles = Given Moles - Used Moles
Excess Moles = 2.08 mol - 1.562 mol
Excess Moles = 0.521 moles
Step 5: Converting Excess moles to Mass as:
Mass = Moles × M.Mass
Mass = 0.521 mol × 12 g/mol
Mass = 6.25 g
