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olya-2409 [2.1K]
3 years ago
8

An atom with a full outer shell will be _______ than an atom with an incomplete outer shell.

Chemistry
1 answer:
skelet666 [1.2K]3 years ago
5 0
B) They are less reactive
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the copper anode is weighed before and after the electrolysis reation. if the copper anode is not completely dry when it is weig
Dmitrij [34]

Answer:

Faraday's constant will be smaller than it is supposed to be.

Explanation:

If the copper anode was not completely dry when its mass was measured, mass of the copper must be heavier than it should have been. Hence, the calculated Faraday’s constant would be smaller than it is supposed to be since when calculating Faraday’s Constant, the charge transferred is divided by the moles of electrons.

5 0
3 years ago
Please answer both questions.
Deffense [45]

Answer:

1)Krypton

2)11H

Explanation:

electrons=protons

protons=atomic number

mass number=protons+neutrons

mass number is the superscript

atomic number is the subscript.

1)The answer is Krypton because its atomic number= number of protons=number of electrons is 36.

mass number is 46+36=82.

2)subscript=atomic number=number of protons=number of electrons

i. H = electrons=1

=neutrons=0

ii. Cl=electrons=17

=neutrons=35-17=18

iii. Na=electrons=11

=neutrons=23-11= 12

so the answer is Hydrogen because it has 1 electron and 0 neutron.

I hope this helps.

6 0
3 years ago
I was born in ……… west.<br><br>complete this sentense with article​
Xelga [282]

Answer:

Article is

I was born in <em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em> west .

4 0
3 years ago
What is oxidation state?​
solniwko [45]

Answer:

a number assigned to an element in chemical combination which represents the number of electrons lost (or gained, if the number is negative), by an atom of that element in the compound

Explanation:

sodium, magnesium, iron is zero.

4 0
3 years ago
Read 2 more answers
A student determines that a 9.8 g mixture of MgCl₂ (s) and NaNO3(s) contains 0.050 mol of
Damm [24]

mass MgCl₂ = mol x MM MgCl₂ = 0.05 x 95.211 g/mol = 4.76 g

mass Cl in MgCl₂ :

= (2 x AM Cl)/MM MgCl₂ x mass MgCl₂

= (2 x 35.5 g/mol)/95.211 g/mol x 4.76

= 3.55 g

% mass Cl in the mixture :

= (mass Cl / mass mixture) x 100%

=  3.55 / 9.8 x 100%

= 36.22%

6 0
2 years ago
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