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olya-2409 [2.1K]
3 years ago
8

An atom with a full outer shell will be _______ than an atom with an incomplete outer shell.

Chemistry
1 answer:
skelet666 [1.2K]3 years ago
5 0
B) They are less reactive
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How much heat does a 100. g sample of copper absorb when its temperature increases by 30.0°C? The specific heat of copper is 0.3
erica [24]

Answer:

\boxed {\boxed {\sf B. \ 1170 \ Joules }}

Explanation:

We are asked to find how much heat a sample of copper absorbs when the temperature is increased.

Since we know the mass, temperature increase, and specific heat capacity, we can use the following formula to calculate heat.

q= mc \Delta T

The mass of the copper sample is 100 grams, the temperature is changed or increased by 30.0 degrees Celsius, and the specific heat of copper is 0.39 Joules per gram degrees Celsius.

  • m= 100 g
  • c= 0.39 J/g °C
  • ΔT= 30.0 °C

Substitute the values into the formula.

q= (100 \ g )(0.39 \ J/g \textdegree C ) (30.0 \textdegree C )

Multiply the first two values. Note that the units of grams cancel.

q= 39 \ J/ \textdegree C (30.0 \textdegree C )

Multiply again, this time the units of degrees Celsius cancel.

q= 1170 \ J

The copper sample absorbs <u>1170 Joules</u> of heat and <u>Choice B </u>is correct.

7 0
3 years ago
PLEASE HELP!!!!!!!
dsp73

Answer: 1. 2Al+3CuCl_2\rightarrow 2AlCl_3+3Cu

2. 3 moles of CuCl_2 : 2 moles of Al

3. 0.33 moles of CuCl_2 : 0.92 moles of Al

4. CuCl_2 is the limiting reagent and Al is the excess reagent.

5. Theoretical yield of AlCl_3 is 29.3 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Al=\frac{25.0g}{27g/mol}=0.92moles

\text{Moles of} CuCl_2=\frac{45.0g}{134g/mol}=0.33moles

The balanced chemical equation is:

2Al+3CuCl_2\rightarrow 2AlCl_3+3Cu  

According to stoichiometry :

3 moles of CuCl_2 require = 2 moles of Al

Thus 0.33 moles of CuCl_2 will require=\frac{2}{3}\times 0.33=0.22moles  of Al

Thus CuCl_2 is the limiting reagent as it limits the formation of product and Al is the excess reagent.

As 3 moles of CuCl_2 give = 2 moles of AlCl_3

Thus 0.33 moles of CuCl_2 give =\frac{2}{3}\times 0.33=0.22moles  of AlCl_3

Theoretical yield of AlCl_3=moles\times {\text {Molar mass}}=0.22moles\times 133.34g/mol=29.3

Thus 29.3 g of aluminium chloride is formed.

5 0
2 years ago
A graduated cylinder is filled with 34.4 mL of water. A toy Car that weighs 43.672-g is Gently placed in the cylinder and the wa
Thepotemich [5.8K]

Answer:9.49g/mL

Explanation:

Mass of toy = 43.672g

Volume of water = 34.4mL

Volume of toy + volume of water = 39mL

Volume of toy = 39 — 34.4 = 4.6mL

Density = Mass /volume

Density = 43.672/4.6 = 9.49g/mL

8 0
3 years ago
What is the formula for Silver (I) chloride?
Kisachek [45]
The formula for Silver (I) chloride is: AgCl
6 0
3 years ago
Read 2 more answers
What is the approximate mass of one mole of oxygen gas (O2)?
fenix001 [56]

The correct answer is B.

1 mol O2  x  15.999 O2/ 1 mol O2 = 15.999 O2

16 O2 when rounded.

3 0
3 years ago
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