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tiny-mole [99]
3 years ago
8

you have a cup of water in a package of powdered juice makes you add some of the Juice mix to the cup of water in the powder dis

solve completely you decide to add more juice to the mix and stir again this time chunks of powder are floating on the surface of the water You can conclude about the solution
Chemistry
1 answer:
Hitman42 [59]3 years ago
8 0

The answer is that there is already enough mixture in the water and it cant dissolve unless you shake it

Hope this helped

~Mr. Nooby

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A volume of 125 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If
VMariaS [17]

Answer:

41.9 g

Explanation:

We can calculate the heat released by the water and the heat absorbed by the steel rod using the following expression.

Q = c × m × ΔT

where,

c: specific heat capacity

m: mass

ΔT: change in temperature

If we consider the density of water is 1.00 g/mol, the mass of water is 125 g.

According to the law of conservation of energy, the sum of the heat released by the water (Qw) and the heat absorbed by the steel (Qs) is zero.

Qw + Qs = 0

Qw = -Qs

cw × mw × ΔTw = -cs × ms × ΔTs

(4.18 J/g.°C) × 125 g × (21.30°C-22.00°C) = -(0.452J/g.°C) × ms × (21.30°C-2.00°C)

ms = 41.9 g

3 0
3 years ago
Carbon monoxide (CO) is a poisonous gas because it binds very strongly to the oxygen carrier hemoglobin in blood. A concentratio
velikii [3]

<u>Answer:</u> The amount of CO that is occupied in the room is 1.98\times 10^3L

<u>Explanation:</u>

We are given:

Concentration of CO = 8.00\times 10^2ppm=800pm by volume

This means that 800\mu L\text{ or }800\times 10^{-6} of CO is present in 1 L of blood

To calculate the volume of cuboid, we use the equation:

V=lbh

where,

V = volume of cuboid

l = length of cuboid = 10.99 m

b = breadth of cuboid = 18.97 m

h = height of cuboid = 11.89 m

V=10.99\times 18.97\times 11.89=2478.83m^3

Converting this into liters, by using conversion factor:

1m^3=1000L

So,  2478.83m^3=2.479\times 10^6L

Applying unitary method:

In 1 L of blood, the amount of CO present is 800\times 10^{-6}

So, in 2.479\times 10^6L of blood, the amount of CO present will be = \frac{800\times 10^{-6}}{1}\times 2.479\times 10^{6}=1983.2L=1.98\times 10^3L

Hence, the amount of CO that is occupied in the room is 1.98\times 10^3L

8 0
3 years ago
Calculate the freezing point of a solution that contains 8.0 g of sucrose (C12H22O11) in 100 g of H2O. Kf for H2O = 1.86C/m
Aleks04 [339]

The freezing point of the sucrose solution is -0.435°C.

<h3>What is the freezing point of the solution?</h3>

The freezing point of the solution is determined from the freezing point depression formula below:

  • ΔT = mKf(H₂O)

Kf(H₂O) = 1.86 Cm

m is molality of solution = moles of solute/mass of solvent

moles of sucrose = 8.0/342.3 = 0.0233 moles

m = 0.0233/0.1 = 0.233 molal

ΔT = 0.233 m * 1.86°C/m.

ΔT = 0.435 °C.

Freezing point of sucrose solution = 0°C - 0.435°C

Freezing point of sucrose solution  = -0.435°C.

In conclusion, the freezing point of sucrose solution is determined from the freezing point depression.

Learn more about freezing point depression at: brainly.com/question/19340523

#SPJ1

8 0
2 years ago
n atom of an element is shown by the model. mc016-1.jpg How is this model useful? It shows how electrons are distributed in the
dolphi86 [110]
I believe it is useful as it shows how electrons are distributed in the shells (energy levels) of an iron atom. An atom is the smallest particle of an element that can take part in a chemical reaction. It contains the nucleus and the shells (energy levels). the nucleus contains protons and neutrons while the shells contain electrons.
7 0
3 years ago
Read 2 more answers
How many numbers of atoms there are in 1.14 mol of (SO3)
Pachacha [2.7K]

called the Avogadro number 

N(A)= 6.02 x 10^23 mol^-1 

1 mole of SO3 will contain 6.02 x 10^23 mol^-1 of SO3 molecules. 

thus, 1.14moles will contain; 

= 1.14mol x [3mol O/1mol SO3] x [6.02 x 10^23

atoms O/1mol O] 

= 2.05884 x 10^24 oxygen atoms 

= 1.14mol x [1mol S/1mol SO3] x [6.02 x 10^23

atoms O/1mol O] 

= 6.8628 x 10^23 sulfur atoms 

hope this helps:-)

8 0
3 years ago
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