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Alex777 [14]
3 years ago
11

What is the difference between a universal law and a scientific theory?

Chemistry
1 answer:
Delvig [45]3 years ago
8 0

your answer is A....

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The first step is in oil is what
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The first step in the oil extraction process is cleaning the olives and removing the stems, leaves, twigs, and other debris left with the olives. The olives should be washed with water to remove pesticides, dirt, etc.  Rocks and sand will damage a hammermill and quickly wear out a centrifugal decanter or oil separator. ;)

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Predict the formula for a compound made from X^2+ and Y^3-
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Compound is X3Y2.

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8 0
4 years ago
The first-order rate constant for the decomposition of N2O5:
kifflom [539]

Answer:

0.0055 mol of N2O5 will remay after 7 min.

Explanation:

The reaction follows a first-order.

Let the concentration of N2O5 after 7 min be y

Rate = Ky = change in concentration of N2O5/time

K is rate constant = 6.82×10^-3 s^-1

Initial concentration of N2O5 = number of moles/volume = 2.1×10^-2/1.8 = 0.0117 M

Change in concentration = 0.0117 - y

Time = 7 min = 7×60 = 420 s

6.82×10^-3y = 0.0117 - y/420

0.0117 - y = 420×6.82×10^-3y

0.0117 - y = 2.8644y

0.0117 = 2.8644y + y

0.0117 = 3.8644y

y = 0.0117/3.8644 = 0.00303 M

Number of moles of N2O5 left = y × volume = 0.00303 × 1.8 = 0.0055 mol (to 2 significant digits)

5 0
3 years ago
Assume that a daily diet of 2000 calories (i.e. 8.37 x 106 J) is converted completely to body heat.
slava [35]

Answer:

(a) the mass of the water is 3704 g

(b) the mass of the water is 199, 285.7 g

Explanation:

Given;

Quantity of heat, H= 8.37 x 10⁶ J

Part (a) mass of water (as sweat) need to evaporate to cool that person off

Latent heat of vaporization of water, Lvap. = 2.26 x 10⁶ J/kg

H = m x Lvap.

m = \frac{H}{L._{vap}} =\frac{8.37 * 10^6.J}{2.26*10^6\ \frac{J}{kg}} = 3.704 \ kg

mass in gram ⇒ 3.704 kg x 1000g = 3704 g

Part (b) quantity of water raised from 25.0 °C to 35.0 °C by 8.37 x 10⁶ J

specific heat capacity of water, C, 4200 J/kg.°C

H = mcΔθ

where;

Δθ is the change in temperature = 35 - 25 = 10°C

m =\frac{H}{c* \delta \theta} = \frac{8.37 *10^6}{4200*10} = 199.2857 kg

mass in gram ⇒ 199.2857 kg x 1000 g = 199285.7 g

5 0
3 years ago
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