When the sugar melted. The sugar was a solid but the became a liquid. I'm pretty sure. :)
Answer:
The correct genotype of the two pure lines and the F1 is:
A⁺A⁺B⁰B⁰C⁰C⁰D⁰D⁰ and A⁰A⁰B⁺B⁺C⁺C⁺D⁺D⁺
The number of additive alleles on each genotype are two and six respectively.
Explanation:
Locus( plural form . loci) are fixed point on a chromosome in which genes are located. These genes are specific genetic material or genotype.
Now;
If we decide to designate the allele of the four loci into either additive (⁺) or non-additive(⁰); we have the following :
Let's the allele of the four loci to be
A⁺/A⁰, B⁺/B⁰, C⁺/C⁰ and D⁺/D⁰
However, from the diagram below; we deduce that the correct genotype for the two pure lines and the F1 is as follows:
A⁺A⁺B⁰B⁰C⁰C⁰D⁰D⁰ and A⁰A⁰B⁺B⁺C⁺C⁺D⁺D⁺ and the number of additive alleles on each genotype are two and six respectively.
The cross between both F1 traits will yield an heterozygous individual for the offspring. i.e A⁺A⁰B⁺B⁰C⁺C⁰D⁺D⁰ with only four additive allele
Radiation. rooms in homes up north have radiators
Answer:
Explanation:
A woman who is a carrier for #1 hemophilia and a man that does not have the
condition have children. What is the probability that they will have a child
with the condition being studied? What is the gender of that child?
if the baby gets the Y chromosome from the father it will be a boy. If the boy gets his mother's X chromosome with the hemophilia gene he will have hemophilia. If he inherits his mother's other X chromosome, he will have normal blood clotting. If the baby gets the X chromosome from the father it will be a girl.
#4 A woman that is heterozygous for type A blood and a man that is heterozygous for type B blood have children. What are the possible blood types of their children?
One parent with A and another with B can produce a child with A, B, AB or O blood types.
#5 Two people are both unknowingly carriers for the cystic fibrosis gene. What is the probability that they will have children with cystic fibrosis?
If both parents are carriers there is a 1 in 4 (25 percent) chance that both will pass on the non-functioning gene, which would result in a pregnancy affected with cystic fibrosis.
#3 A woman that is heterozygous for Huntington's disease and a man that does not have the condition have children . What is the probability that their children inherit the Huntington's gene ?
Huntington's disease (HD) is what is called a dominant genetic disease. What this usually means is that a child only has a chance of getting a disease like this if a parent has it too. But parents without HD can have a child with HD. This is true of any dominant genetic disease
Answer:
I am confused on what you are saying
Explanation:
