Answer:
Step-by-step explanation:
let : x The length and y the width you have this system :
xy =60....(1)
x = y+10...(2)
put the value for x in (1): (y+10)y =60
the quadratic equation is : y² +10y - 60 = 0
Δ =b² - 4ac a = 1 b= 10 c= - 60
Δ =10² - 4(1)(-60) = 324 =18²
y 1 = (-10-18)/2 negatif...... refused
y 2 = (-10+18)/2 =4
the width is 4
Answer:
(d) All of the above
Step-by-step explanation:
In order to solve this question we will have to find out which numbers are located in which group (the group of numbers are U, B, B').
So lets start of with finding out what numbers are a part of group U. By looking at that picture we can see that all number on the graph are a part of group U. So.....
U = {0,1,2,3,4,5,6,7,8,9}
Then we can find out what numbers are part of the group B. We just have to include the numbers that are located within the circle and exclude all of the numbers out side of the circle. So........
B = {0,1,4,5,6,7,8}
We find numbers that are parts of group B' by using a similar method that we used to find out what numbers were part of group B (Just this time we include all numbers outside of the circle and exclude all of the numbers inside the circle). So ......
B' = {2,3,9}
Now we see that the right option is option d.
Answer:
please refer the the photo bellow
answer is C. 74 degree
Step-by-step explanation:
ANSWER
(A)csc angle C equals 3 over 2
EXPLANATION
The cosecant is hypotenuse over opposite.



The secant is the hypotenuse over adjacent.



The only correct choice is A
Answer:
Cody has solved (12 × 12) = 144 problems.
Step-by-step explanation:
For every one problem that Julia completes, Cody completes twelve.
If Julia Completes x problems and Cody completes y problems, then we can write y = 12x ........ (1)
Now, given that the number of problems solved by Cody is one hundred twenty more than two times the number of problems solved by Julia.
Hence, 2x + 120 = y ......... (2)
Now, from equations (1) and (2) we get,
2x + 120 = 12x
⇒ 10x = 120
⇒ x = 12
Therefore, Cody has solved (12 × 12) = 144 problems. (Answer)