Let the speed for the first 12 mi be x mi/h, the speed for 18 mi was (x+4) mi/h
thus given that
time=distance/speed
the average time will be:
3=(12+18)/(x+x+4)
3=30/(2x+4)
solving for x we get
3(2x+4)=30
6x+6=30
6x=24
x=4 mi/hr
Answer: 12 mi/hr
Answer:
The installations at the Maumee branch would you expect to take more than 30 minutes is 10.
Step-by-step explanation:
Consider the provided information.
Let x is the installations at the Maumee branch take more than 30 minutes.
The work standards department at corporate headquarters recently conducted a study and found that 20% of the mufflers were not installed in 30 minutes or less.
Therefore, π=0.20
The Maumee branch installed 50 mufflers last month.
Thus, n=50
Mean of the distribution: μ=nπ
Substitute the respective values in the above formula.
μ=(50)(0.20)
μ=10
Hence, the installations at the Maumee branch would you expect to take more than 30 minutes is 10.
Answer:
A. 2,310 sq ft
Step-by-step explanation:
<u>R</u><u>e</u><u>c</u><u>t</u><u>e</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>b</u><u>e</u><u>l</u><u>o</u><u>w</u><u>:</u>
- A = l × b
- A = 74 × 15
- A = 1,110ft
<u>Rectangle Above</u><u>:</u>
- A = l × b
- A = 50 × 24
- A = 1,200ft
<u>A</u><u>r</u><u>e</u><u>a</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>P</u><u>l</u><u>a</u><u>y</u><u>g</u><u>r</u><u>o</u><u>u</u><u>n</u><u>d</u><u>:</u>
- 1,110ft + 1,200ft
- 1,310 sq ft (A)
Answer:
x1 = -4; x2 = 10
Step-by-step explanation:
1) Expand the module as two separate equations:
x - 3 = 7
x - 3 = -7
2) Solve the equations:
x = 10
x = -4
=> x1 = -4; x2 = 10
Ok, so here your being asked to solve 6x2<span> + 5x = -7
The procedure that I did was using this formula it led me to get the following:
</span>Using the formula:
x = -(-5) ± √(-5)² - 4(6)(-6)/ 2(6)
x = 5 ± √ 25 + 144 / 12
x = 5 ± √ 169 / 12
x = 5 ± 13/12
x1 = 5 + 13/12
x1 = 18/12
x1 = 3/2
x2 = 5 - 13/12
x2 = -8/12
<span>
x2 = - 2/3
Hope this helped :)</span>