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3 years ago

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Which describes an object's velocity that changes by the same amount each second? constant acceleration constant time constant s

peed constant displacement

2 answers:

Alex777 [14]3 years ago

4 0

Constant acceleration

because when the object's velocity is changing then the object is accelerating or decelerating
as acceleration describe changing of velocity so the answer is constant acceleration

Hope I can help u

kaheart [24]3 years ago

3 0

Answer:

Explanation:

Acceleration is defined as the rate of change of velocity.

Acceleration = (Change in velocity) / time taken

Acceleration = (Final velocity - initial velocity) / time

As the object velocity changes by the same amount in each second, it means the acceleration is constant.

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A roller coaster has a "hump" and a "loop" for riders to enjoy (see picture). The top of the hump has a radius of curvature of 1

aivan3 [116]

Answer:

Part a)

$F_n = 306 N$

Part b)

$v = 12.1 m/s$

So this speed is independent of the mass of the rider

Explanation:

Part a)

By force equation on the rider at the position of the hump we can say

$mg - F_n = ma_c$

now we will have

$mg - F_n = \frac{mv^2}{R}$

$F_n = mg - \frac{mv^2}{R}$

now we have

$F_n = 100(9.81) - \frac{100(9^2)}{12}$

$F_n = 981 - 675$

$F_n = 306 N$

Part b)

At the top of the loop if the minimum speed is required so that it remains in contact so we will have

$F_n + mg = ma_c$

$F_n = 0$ at minimum speed

$mg = \frac{mv^2}{R}$

$v = \sqrt{Rg}$

$v = \sqrt{15 \times 9.81}$

$v = 12.1 m/s$

So this speed is independent of the mass of the rider

5 0

3 years ago

Pls help I’m being timed!!

Firdavs [7]

Answer:

B

Explanation:

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6 0

3 years ago

Read 2 more answers

A soccer player icks a rock horizontally off a 40m high cliff into a pool f water if the player hears the sound of the splash s

Semenov [28]

Answer:

v = 9.936 m/s

Explanation:

given,

height of cliff = 40 m

speed of sound = 343 m/s

assuming that time to reach the sound to the player = 3 s

now,

time taken to fall of ball

$t = \sqrt{\dfrac{2s}{g}}$

$t = \sqrt{\dfrac{2\times 40}{9.8}}$

t = 2.857 s

distance

d = v x t

d = v x 2.875

time traveled by the sound before reaching the player

$t_0 = t - t_{fall}$

$t_0 = 3 - 2.875$

$t_0 = 0.143 s$

distance traveled by the wave in this time'

r = 0.143 x 343

r= 49.05 m

now,

we know.

d² + h² = r²

d² + 40² = 49.05²

d =28.387 m

v x 2.875=28.387 m

v = 9.936 m/s

7 0

3 years ago

A centrifuge in a biology laboratory rotates at an angular speed of 3,400 rev/min. When switched off, it rotates 48.0 times befo

IgorLugansk [536]

Answer:

- 210 rad/s²

Explanation:

n = frequency of rotation = 3400/60 = 170/3 per sec.

angular velocity ω ( 0 ) at time 0 = 2π n = 2π x 170/3

angular velocity at time t = ω(t) = 0

now, ω²( t) = w²(o) + 2α Φ ( α = angular acceleration and Φ = angular displacement) = 2π x 48 rad.

0 = ( 2π x 170/3 )² + 2α x 48 x 2π

α = - (2π x 170 x 170 )/ (3 x 3 x 2 x 48 ) = 210 rad / s²

7 0

3 years ago

While filming an intense action sequence for the next James Bond movie, a controlled explosion detonates 1.3 km away from the ac

brilliants [131]

To solve this problem we must basically resort to the kinematic equations of movement. For which speed is defined as the distance traveled in a given time. Mathematically this can be expressed as

$v = \frac{d}{t}$

Where

d = Distance

t = time

For which clearing the time we will have the expression

$t = \frac{d}{v}$

Since we have two 'fluids' in which the sound travels at different speeds we will have that for the rock the time elapsed to feel the explosion will be:

$t = \frac{1300m}{3000m/s}$

$t = 0.433s$

In the case of the atmosphere -composite of air- the average speed of sound is 343m / s, therefore it will take

$t = \frac{1300m}{343m/s}$

$t = 3.79s$

The total difference between the two times would be

$\Delta t = 3.79s-0.433s$

$\Delta t = 3.357s$

Therefore 3.357s will pass between when they feel the explosion and when they hear it

8 0

3 years ago