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Alexxx [7]
3 years ago
10

Which describes an object's velocity that changes by the same amount each second? constant acceleration constant time constant s

peed constant displacement
Physics
2 answers:
Alex777 [14]3 years ago
4 0
Constant acceleration

because when the object's velocity is changing then the object is accelerating or decelerating
as acceleration describe changing of velocity so the answer is constant acceleration

Hope I can help u
kaheart [24]3 years ago
3 0

Answer:

Explanation:

Acceleration is defined as the rate of change of velocity.

Acceleration = (Change in velocity) / time taken

Acceleration = (Final velocity - initial velocity) / time

As the object velocity changes by the same amount in each second, it means the acceleration is constant.

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Calculate the net force on the right charge due to the other two. Enter a positive value if the force is directed to the right a
lbvjy [14]

Answer:

Answer:

A. - 0.017N. It acts to the left.

B. - 0.043N. It acts to the left.

C. 0.060N. It acts to the right.

Explanation:

A. For the +65μC charge, we consider it to be the origin. Hence, the two other charges are on the +x axis.

The net coulombs force on the charge is

F = [KQ(1)Q(2)]/(r^2) + [KQ(1)Q(3)]/(r^2)

Where K = Coloumbs constant =

Q(1) = charge on the leftmost side.

Q(2) = charge in the middle.

Q(3) = charge on the rightmost side.

F = [(8.988 × 10^9)×(65×10^-6)×(48×10^-6)]/(40^2) + [(8.988 × 10^9)×(-95×10^-6)×(65×10^-6)]/(40^2)

F = 0.01753 - 0.03469

F = -0.017N

It has a negative sign, hence, it acts to the left.

B. For the +48μC charge, we consider it to be the origin. Hence, the leftmost charge is on the - x axis and the rightmost charge is on the +x axis.

The net coulombs force on the charge is

F = [-KQ(1)Q(3)]/(r^2) + [KQ(2)Q(3)]/(r^2)

F = [-(8.988×10^9)×(65×10^-6)×(48×10^-6)]/(40^2) + [(8.988 × 10^9)×(48×10^-6)×(-95×10^-6)]/(40^2)

F = -0.017 - 0.02562

F = - 0.043N

It has a negative sign, hence, it acts to the left.

C. For the -95μC charge, we consider it to be the origin. Hence, the two other charges are on the - x axis.

The net coulombs force on the charge is

F = [-KQ(1)Q(3)]/(r^2) - [KQ(2)Q(3)]/(r^2)

F = [-(8.988×10^9)×(65×10^-6)×(-95×10^-6)]/(40^2) - [(8.988 × 10^9)×(48×10^-6)×(-95×10^-6)]/(40^2)

F = +0.03469 + 0.02562

F = +0.060N

It has a positive sign, hence, it acts to the right.

Read more on Brainly.com - brainly.com/question/14592748#readmore

Explanation:

5 0
4 years ago
A roofer needs to get shingles onto a roof. Pulling the shingles up manually uses 1,549 N or force. The roofer decides to use a
joja [24]

Answer:

Mechanical advantage of pulleys = 3.47 (Approx)

Explanation:

Given:

Manual force = 1,549 N

Pulleys force = 446 N

Find:

Mechanical advantage of pulleys

Computation:

Mechanical advantage of pulleys = Manual force / Pulleys force

Mechanical advantage of pulleys = 1,549 / 446

Mechanical advantage of pulleys = 3.4730

Mechanical advantage of pulleys = 3.47 (Approx)

3 0
4 years ago
What is TeO3 compound name​
Stolb23 [73]

Tellurium trioxide

Hope this helps you!!!

4 0
3 years ago
Read 2 more answers
a football is thrown upward at a 31° angle to the horizontal.the acceleration of gravity is 9.8m/s^2. To throw the ball a distan
mr Goodwill [35]

The ball's vertical position y in the air at time t is

y=v_0\sin31^\circ\,t-\dfrac g2t^2

The ball is at its original height when y=0, which happens at

v_0\sin31^\circ\,t-\dfrac g2t^2=\dfrac t2\left(2v_0\sin31^\circ-gt)=0

\implies t=0\text{ and }t=\dfrac{2v_0\sin31^\circ}g

Meanwhile, the ball's horizontal position x at time t is

x=v_0\cos31^circ\,t

So when the ball reaches its original height a second time, the ball will have traveled a horizontal distance of

x=\dfrac{2{v_0}^2\sin31^\circ\cos31^\circ}g=\dfrac{{v_0}^2\sin(2\cdot31^\circ)}g

(which you might recognize as the formula for the range of a projectile)

To reach a distance of x=77\,\rm m, the initial speed v_0 would be

77\,\mathrm m=\dfrac{{v_0}^2\sin62^\circ}{9.8\,\frac{\rm m}{\mathrm s^2}}\implies v_0=29\dfrac{\rm m}{\rm s}

7 0
3 years ago
An astronaut is on the moon. He drops a hammer from a height of 3.2metres and it takes 2.0 seconds to reach the lunar landscape.
Anvisha [2.4K]

Answer:

1/6 m/s^2      ( about 1/6th gravity of Earth ( 9.81 m/s^2)

Explanation:

Displacement =  yo  +  vo t  - 1/2 a t^2

      -  3.2          = 0     +  0     - 1/2 a(2.0)^2

      -     3.2       =                -2a

             a = 3.2 / 2 = 1.6 m/s^2

6 0
2 years ago
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