An object is positively charged if it has more what

Rank in order, from largest to smallest, the magnitudes of the electric field at the black dot. A. 2, 1, 3, 4 B. 1, 4, 2, 3 C. 3

sweet [91]

Given that,

Rank in order from largest to smallest the magnitude of the electric field at block dot.

Electric field :

Electric field is proportional to the charge divided by square of distance.

In mathematically,

$E\propto\dfrac{q}{r^2}$

Where, q = charge

r = distance

If the charge is greater then electric field will be greater.

If the distance is greater then electric field will be smaller.

We need to find the electric field at black dot

According to figure,

(I). The electric field at black dot due to positive charge point q to left. the distance is r.

The electric field will be

$E=\dfrac{kq}{r^2}$

The electric field will be largest.

(II). The electric field at black dot due to positive charge point 2q to left. The distance is 2r.

Then, the electric field will be

$E=\dfrac{k2q}{(2r)^2}$

$E=\dfrac{kq}{2r^2}$

The electric field will be smallest.

(III). The electric field at black dot due to positive charge point 2q to left. The distance is r.

Then, the electric field will be

$E=\dfrac{k2q}{(r)^2}$

The electric field will be very largest.

(IV). The electric field at black dot due to positive charge point q to left. The distance is 2r.

Then, the electric field will be

$E=\dfrac{kq}{(2r)^2}$

$E=\dfrac{kq}{4r^2}$

The electric field will be very smallest.

So, The electric field from largest to smallest will be

$E_{3}>E_{1}>E_{2}>E_{4}$

Hence, The ranking will be 3, 1, 2, 4.

(D) is correct option.

4 0

3 years ago

The pressure in a section of horizontal pipe with a diameter of 2.5 cm is 139 kPa. Water ï¬ows through the pipe at 2.9 L/s. If t

My name is Ann [436]

Answer:

d = 2*0.87 = 1.75 cm

Explanation:

by using flow rate equation to determine the speed in larger pipe

$\phi =\pi r^2 v$

$v = \frac{\phi}{\pi r^2}$

$= \frac{2900 cm^3/s}{3.14(1.25cm)^2}$

= 591.10 cm/s

= 5.91 m/s

by Bernoulli's EQUATION

$p1 +\frac{1}{2} \rho v1^2 = p2 +\frac{1}{2} \rho v2^2$

$139000+ \frac{1}{2}*1000*5.91^2 = 101000 +\frac{1}{2}*1000* v2^2$

solving for v2

v2 = 10.53 m/s

diameter can be determine by using flow rate equation

$q = v \pi r^2$

$r^2 = \frac{q}{\pi v}$

$= \frac{2900}{3.14*1053}$

r = 0.87 cm

d = 2*0.87 = 1.75 cm

5 0

3 years ago

A 7 kg ball of clay traveling at 12 m/s collides with a 25 kg ball of clay traveling in the

ANEK [815]

Answer:

Given: 

m1 = 7 kg

V1 = 12 m/s

m2 = 25 kg

V2 = 6 m/s

To find:

Combined speed of two balls stick together after collision V = ?

Solution:

According to law of conservation of momentum,

m1V1 + m2V2 = (m1+m2)V

7×12 + 25×6 = (7+25)V

84 + 150 = 32V

V = 234/32

V = 7.31 m/s

Combined speed of two ball is 7.31 m/s

Thanks for joining brainly community!

4 0

2 years ago

In the figure below consider R = 11 Ω. Calculate the equivalent resistance.

nalin [4]

Answer:42R/41

Explanation:

R/2+R=3R/2

1/r=1/(3R/2)+1/R

1/r=2/3R+1/R

1/r=5/3R

5r=3R

r=3R/5

3R/5+3R/2=21R/10

1/r=1/2R+1/2R

1/r=1/R

r=R

R+R=2R

1/r=1/2R +1/(21R/10)

1/r=1/2R+10/21R

1/r=41/42R

41r=42R

r=42R/41

7 0

4 years ago

A student is playing with a radio-controlled race car on the balcony of a sixth-floor apartment. An accidental

pentagon [3]

Answer:

No, it is independent

Explanation:

As we know that car is moving horizontally

so the vertical component of the speed is zero initially

so in order to hit the ground we know that

$\Delta y = v_y t + \frac{1}{2}at^2$

so here we know that

$h = 0 + \frac{1}{2}gt^2$

on solving above equation for time

$t = \sqrt{\frac{2h}{g}}$

so we will say that it will not depends on the initial horizontal speed

8 0

4 years ago

An object is positively charged if it has more what​

An object is positively charged if it has more what