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sasho [114]
4 years ago
8

To practice Problem-Solving Strategy 2.1 Motion with constant acceleration You are driving down the highway late one night at 20

m/s when a deer steps onto the road 35 m in front of you. Your reaction time before stepping on the brakes is 0.50 s , and the maximum deceleration of your car is 10 m/s2 . How much distance is between you and the deer when you come to a stop?
Physics
1 answer:
atroni [7]4 years ago
5 0

Answer:

5 m

Explanation:

First, we need to find the distance traveled by car in the 0.50 s:

x = v*t = 20 m/s*0.5 s = 10 m

Now, we can find the distance traveled by car when the brakes are applied:

V_{f}^{2} = V_{0}^{2} - 2ax

x = \frac{V_{0}^{2}}{2a} = \frac{(20 m/s)^{2}}{2*10 m/s^{2}} = 20 m

Finally, the distance between the car and the deer is:  

d = 35 m - 10 m - 20 m = 5 m

Therefore, the distance between the car and the deer is 5 m.

I hope it helps you!

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Two general points to remember for recovering from skids are: keep your eyes pointed in the direction you want to go and you wil
Semmy [17]
The answer is do not break, the key avoiding skids is to always smoothly apply your brakes and accelerator and to turn slowly and smoothly. Reducing of the speed before oncoming turns and once driving in possibly hazardous circumstances such as wet, icy or snow covered roadways or on roadways with loose gravel.  
8 0
4 years ago
After a long night of cramming for a test, your college roommate hits his head forcefully against the wall of your room in despa
sweet [91]

Answer:

See the answer below

Explanation:

Newton's third law states that for every action, there will always be an opposing reaction of equal magnitude to the action.

<em>Hence, the wall will exert an equal opposing force to the head and the roommate will feel this opposing force as pains and/or headache. </em>

3 0
3 years ago
In billiards, the 0.165 kg cue ball is hit toward the 0.155 kg eight ball, which is stationary. The cue ball travels at 5.8 m/s
Damm [24]

Answer:

another ball velocity = 3.92 m/s and with 30° clockwise from initial direction

Explanation:

given data

mass m1 = 0.165 kg

mass m2 = 0.155 kg

before collision velocity v1 = 5.8 m/s

before collision velocity v2 = 0

angle =  35.0° from initial direction

after collision 1st ball velocity v3 = 3.2 m/s

to find out

after collision another ball velocity v4

solution

we consider here ball move in x axis and after collision 1st ball move upside of x axis with angle 35 degree and other ball move downside with x axis with angle θ

so from conservation of momentum we say

m1v1 = m1v3cos35 + m2v4cosθ   with x axis    .............1

m1v3sin35 = m2v4sinθ                   with y axis  .............2

so from 1 equation

0.165 × 5.8 = 0.165(3.2)cos35 + 0.155(v4)cosθ

v4 cosθ  = 3.38                                            .................3

form 2 equation

0.165(3.2)sin35 = 0.155(v4)sinθ  

v4 sinθ = 1.95                                              ......................4

so magnitude of another ball velocity is square and adding equation 3 and 4

another ball velocity = √(3.39²+1.96²)

another ball velocity = 3.92 m/s

and direction is tanθ = 1.96/3.39

θ = 30° clockwise from initial direction

3 0
3 years ago
Please answer this fast <br>I 'll marks them brainliest answer <br>​
Reptile [31]

answer

64 is C (c) 1-Bromo-3-methylbutane

63 is D

i is secondary ii is primary

8 0
3 years ago
Ques
Amanda [17]

Answer:

When a particle or a system of particles move in a system where no external force acts, then the total linear momentum of the particle system remains constant.

Explanation:

Given data:

Total mass of the skateboarder, m_{1} = 70 \ kg

Mass of the friend, m_{2} = 50 \ kg

Initial velocity of the skateboarder, u_{1} = 3 \ m/s

Initial velocity of the the friend, u_{2} = 0

Let the new velocity of the skateboarder when his friend jumps be v.

From the conservation law of linear momentum,

m_{1}u_{1} + m_{2}u_{2} = (m_{1} + m_{2})v

70 \times 3 + 50 \times 0 = (70 + 50)v

\Rightarrow \ v &= 1.75 \ m/s.

4 0
4 years ago
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