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N76 [4]
3 years ago
13

The rate of change of velocity or speed is known as acceleration. If a car increases it speed form 10 to 20m/s in 2 seconds, the

n what is its rate of change in velocity?
A) 5 m/s/s
B) 10 m/s/s
C) 20 m/s/s
D) 40 m/s/s
Physics
1 answer:
lisov135 [29]3 years ago
7 0

Answer:

A) 5 m/s/s

Explanation:

<u>Given the following data;</u>

Initial velocity = 10m/s²

Final velocity = 20m/s²

Time, t = 2 seconds.

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

Acceleration, a = \frac{final \; velocity  -  initial \; velocity}{time}

Substituting into the equation, we have;

Acceleration, a = \frac{20 - 10}{2}

Acceleration, a = \frac{10}{2}

<em>Acceleration, a = 5m/s²</em>

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Point A and B located at 4 meters and 9 meters from a source of the sound. If IA and IB are intensity at point A and point B, th
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The intensity ratio at point A and B will be 81:16.

<u>Explanation:</u>

Sound waves are known to get faded with increase in the distance. This is because, the intensity of the sound is inversely proportional to the square of the distance of the source from the observer. So, if an observer is standing greater distance from the source of the sound, he/she will find difficulty in hearing the sound.

So, as the distance between the source and observer increases, the intensity of the sound wave decreases.

I = \frac{1}{r^{2} }

As here two points A and B are located at 4 m and 9 m distance from the source, then the intensity of sound at A and B will be inversely proportional to their respective square of the distance as shown below.

I_{A} =\frac{1}{r_{A}^{2}  }  = \frac{1}{4 \times 4}=\frac{1}{16}

Similarly,

I_{B} =\frac{1}{r_{B}^{2}  }  = \frac{1}{9 \times 9}=\frac{1}{81}

So, the ratio of intensity at point A and B will be

\frac{I_{A} }{I_{B} } = \frac{81}{16} =81:16

Thus, the intensity ratio at point A and B will be 81:16.

7 0
3 years ago
Two masses are joined by a mass less string. A 33-N force applied vertically to the upper mass gives the system a constant upwar
lisov135 [29]

Lower mass: 1.20 kg, upper mass: 1.28 kg

Explanation:

In order to solve the problem, we consider the forces acting on the upper mass only first.

The upper mass is acted upon three forces:

  • The applied force F_a=33 N, upward
  • The weight of the mass itself, m_u g, where m_u is the upper mass and g=9.8 m/s^2 is the acceleration of gravity, downward
  • The tension in the string, T=16 N, downward

Therefore, the equation of the forces for the upper mass is:

F_a - m_u g - T = m_u a

where

a=3.5 m/s^2 is the acceleration (upward)

Solving for m_u,

m_u = \frac{F_a-T}{a+g}=\frac{33-16}{3.5+9.8}=1.28 kg

Now we can find the lower mass by considering the forces acting on it:

  • The tension in the string, T = 16 N, upward
  • The weight of the mass itself, m_L g, where m_L is the lower mass, downward

So the equation of the forces is

T-m_L g = m_L a

And solving for the mass,

m_L = \frac{T}{a+g}=\frac{16}{3.5+9.8}=1.20 kg

Learn more about acceleration and forces:

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#LearnwithBrainly

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Zolol [24]
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Nataly [62]

Answer:

D.) Blue

Explanation:

because Blue is a higher frequency and therefore corresponds to a higher energy level transition.

I hope this helped you :)

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