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Delicious77 [7]
3 years ago
6

The intensity of sunlight under the clear sky is 1160 w/m2 . how much electromagnetic energy is contained per cubic meter near t

he earth's surface? the speed of light is 2.99792 × 108 m/s. answer in units of j/m3
Physics
1 answer:
Reil [10]3 years ago
5 0

Answer:

= 3.869 × 10^-6 J/m³

Explanation:

Intensity is given as W/m^2 which is equivalent to J/ (s*m^2)

Speed of light is 2.99792 × 10^8 m/s.

Therefore;

Electromagnetic energy per cubic meter = Intensity/speed of light

      = 1160 J/ (s*m³)/ 2.99792 × 10^8 m/s.

      <u>= 3.869 × 10^-6 J/m³</u>

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A block of mass M1 = 288.0 kg sits on an inclined plane and is connected to a bucket with a massless string over a massless and
AlekseyPX

Answer:

M2 = 278.06 kg

Explanation:

We calculate the weight of M1

W=m*g

Where

m: mass (kg)

g: acceleration due to gravity (m/s²)

W₁=288* 9.8= 2822.4 N

Look at the attached graphic

We calculate the x-y components of the weight :

W₁x= 2822.4*sin41° N =1851.66 N

W₁y= 2822.4 *cos41° N = 2130.09 N

We apply Newton's first law for the balance in M1:

Σ Fy=0

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Fn=W₁y=2130.09N

Friction Force = Ff=μs *Fn = 0.41*2130.09 =873.34 N

Σ Fx=0

T- W₁x- Ff=0

T= 1851.66 + 873.34

T= 1851.66 + 873.34

T=2725 N

We apply Newton's first law for the balance in M2:

Σ Fy=0

T- W₂ =0

W₂ = T = 2725 N

W₂ = M2*g

M2 = W₂/g

M2 = 2725/9.8

M2 = 278.06 kg

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