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eimsori [14]
3 years ago
11

Benzene has a formula of C6H6 and a vapor pressure of 96.4 torr at 298 K. Toluene has a formula of C7H8 and a vapor pressure of

28.9 torr at 298 K. If a solution is made of 299 g of toluene and 391 g of benzene, what is the vapor pressure of the solution?
Chemistry
1 answer:
Slav-nsk [51]3 years ago
6 0

Answer: The vapor pressure of the solution is 55.2 torr

Explanation:

p_1=x_1p_1^0 and p_2=x_2P_2^0

where, x = mole fraction in solution

p^0 = pressure in the pure state

According to Dalton's law, the total pressure is the sum of individual pressures.

p_{total}=p_1+p_2p_{total}=x_Ap_A^0+x_BP_B^0

x = mole fraction = \frac{\text {moles}}{\text {total moles}}

Given : 299 g of toluene and 391 g of benzene.

moles of toluene = \frac{\text{Given mass}}{\text {Molar mass}}=\frac{299g}{92g/mol}=3.25moles

moles of benzene= \frac{\text{Given mass}}{\text {Molar mass}}=\frac{391g}{78g/mol}=5.01moles

Total moles = moles of solute (toluene)  + moles of solvent (benzene) = 3.25 + 5.01 = 8.26

x_{benzene} = mole fraction of benzene =\frac{3.25}{8.26}=0.39

x_{toluene} =mole fraction of toluene = (1-0.39) = 0.61

p_{benzene}^0=96.4torr

p_{toluene}^0=28.9torr

p_{total}=0.39\times 96.4+0.61\times 28.9=55.2torr

Thus the vapor pressure of the solution is 55.5 torr

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