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Gemiola [76]
2 years ago
9

How is the life cycle of a star similar to that of a human?

Chemistry
2 answers:
VLD [36.1K]2 years ago
7 0

Answer:

The most common similarity is that they live and die

Explanation:

Arturiano [62]2 years ago
6 0

Answer: They both have stages where they are born and die which is in the main sequence and supernova and in a human they are born in a womb and die of old age.

Explanation:

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What does the survival of the fittest mean
Tomtit [17]
It means that the fit and well adjusted ones thrive and "make it", and the weak ones that can't adapt die.
7 0
3 years ago
Convert 3.30 g of copper (II) hydroxide Cu(OH)2 to molecules.
ratelena [41]

Answer:

0.18× 10²³ molecules

Explanation:

Given data:

Mass of copper hydroxide = 3.30 g

Number of molecules = ?

Solution:

Number of moles = mass/molar mass

Number of moles = 3.30 g/97.56 g/mol

Number of moles = 0.03 mol

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

0.03 mol × 6.022 × 10²³ molecules / 1mol

0.18× 10²³ molecules

6 0
2 years ago
Convert -12.00 degrees Celsius to the unit Kelvin. 296.15 K 261.15 K -285.15 K -162.85 K
Gre4nikov [31]

To convert Celsius to kelvin, we need to know the formula. Kelvin = Celsius + 273.15. Now, we can figure out how many degrees kelvin -12 degrees Celsius is.


Kelvin = -12 + 273.15

Kelvin = 261.15

7 0
3 years ago
Can someone help me answer these ?
g100num [7]

3.3 ثنائي ميثيل الهكسان

5 0
3 years ago
Consider the reaction 2Al + 6HBr → 2AlBr3 + 3H2. If 8 moles of Al react with 8 moles of HBr, what is the limiting reactant?
TiliK225 [7]

Answer:- HBr is limiting reactant.

Solution:- The given balanced equation is:

2Al+6HBr\rightarrow 2AlBr_3+3H_2

From this equation, There is 2:6 mol or 1:3 mol ratio between Al and HBr. Since we have 8 moles of each, HBr is the limiting reactant as we need 3 moles of HBr for each mol of Al.

The calculations could be shown as:

8molAl(\frac{6molHBr}{2molAl})

= 24 mol HBr

From calculations, 24 moles of HBr are required to react completely with 8 moles of Al but only 8 moles of it are available. It clearly indicates, HBr is limiting reactant.

7 0
3 years ago
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