Answer:
<u>Mass concentration (g/L) </u><u><em>= 2.49g/L.</em></u>
Explanation:
No. of moles = 
= 
= 0.001245 moles
Concentration of KHP (C1) in litres = n/v
= 
= 0.062 mol/L
We know that:
= 
where c1v1 and c2v2 are the products of concentration and volumes of KHP and NaOH respectively.
Since mole ratio is 1 : 1.
1 mole of NaOH - 40g
0.001245 mole of NaOH = 40 × 0.001245 = 0.0498g
⇒0.0498g of NaOH was used during the titration
<u><em>∴Mass concentration (g/L) = 0.0498g ÷ 0.02L</em></u>
<u><em>= 2.49g/L.</em></u>
Answer:
B. Ca2+ import into the ER because it has the steeper concentration gradient
Explanation:
ΔGt = RT㏑(C₂/C₁)
where ΔGt is the free energy change for transport; R = 8.315 J/mol; T = 298 K; C₂/C₁ is ratio of concentrations inside and outside each organelle.
For Ca²⁺ import
ΔGt = 8.315 J/mol * 298 K * ㏑(10⁻³/10⁻⁷)
ΔGt= 3.42 kJ/mol
For H⁺ import
ΔGt = 8.315 J/mol * 298 K * ㏑ (10⁻⁴/10⁻⁷)
ΔGt = 2.73 kJ/mol
From the above values, ΔGt is greater for Ca²⁺ import because it has a steeper concentration gradient
Hey there!:
K = Ka * Kb / Kw
Ka = 1.8*10⁻⁴
Kb = 10⁻¹⁴ / 6.8*10⁻⁴
K = 1.8*10⁻⁴ * ( 10⁻¹⁴/ 6.8*10⁻⁴ ) * ( 1 / 10⁻¹⁴ )
K = = 1.8 / 6.8
K = 0.265
Answer A
Therefore:
K is less than on the forward reaction is not favorable .
Hope That helps!
Answer:
a correct Lewis diagram for CO2 would look something like this
Explanation:
One C and 2 O. Both O have 4 extra dots and 2 lines/bonds to the C. C has no extra dots.
Hope this helps!
Answer:
1)Filtration to remove sand
2)Evaporation to obtain sugar
Explanation:
Add water to the mixture and mix,sugar will dissolve.
Filter out the sand.
Evaporate the remaining solution to obtain the sugar.
