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3 years ago

Figure 1

Chemistry

1 answer:

mel-nik [20]3 years ago

7 0

The process of fertilization occurs externally in frogs.

<h2>Stages of lifecycle</h2>

A full growth of frog occurs when it passes through five stages of its life cycle. During a frog's metamorphosis, an egg will hatch and a tadpole appear in which the back legs emerge first, then front legs, and finally it become a full grown adult frog.

A frog's eggs are found in water because they do not have a hard protective shell like birds and reptiles. The frog's eggs are covered with a glycoprotein, which helps to keep the eggs moist so that's why the frog lays its eggs in water in order to prevent them from drying.

<h3>Fertilization</h3>

In most species of frogs, fertilization occurs externally. The male frog grabs the female's back and fertilizes the eggs as the female frog releases the eggs. Those eggs which receives the sperm will fertilized so we can conclude that the process of fertilization occurs externally in frogs.

Learn more about growth here: brainly.com/question/25630111

Learn more: brainly.com/question/26032527

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The element iridium exists in nature as two isotopes: 191Ir has a mass of 190.9606 u, and 193Ir has a mass of 192.9629 u. The av

nlexa [21]

<u>Answer:</u> The percentage abundance of $_{77}^{191}\textrm{Ir}$ and $_{77}^{193}\textrm{Ir}$ isotopes are 37.10% and 62.90% respectively.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of $_{77}^{191}\textrm{Ir}$ isotope be 'x'. So, fractional abundance of $_{77}^{193}\textrm{Ir}$ isotope will be '1 - x'

<u>For $_{77}^{191}\textrm{Ir}$ isotope:</u>

Mass of $_{77}^{191}\textrm{Ir}$ isotope = 190.9606 amu

Fractional abundance of $_{77}^{191}\textrm{Ir}$ isotope = x

<u>For $_{77}^{193}\textrm{Ir}$ isotope:</u>

Mass of $_{77}^{193}\textrm{Ir}$ isotope = 192.9629 amu

Fractional abundance of $_{77}^{193}\textrm{Ir}$ isotope = 1 - x

Average atomic mass of iridium = 192.22 amu

Putting values in equation 1, we get:

$192.22=[(190.9606\times x)+(192.9629\times (1-x))]\\\\x=0.3710$

Percentage abundance of $_{77}^{191}\textrm{Ir}$ isotope = $0.3710\times 100=37.10\%$

Percentage abundance of $_{77}^{193}\textrm{Ir}$ isotope = $(1-0.3710)=0.6290\times 100=62.90\%$

Hence, the percentage abundance of $_{77}^{191}\textrm{Ir}$ and $_{77}^{193}\textrm{Ir}$ isotopes are 37.10% and 62.90% respectively.

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3 years ago

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aleksklad [387]

Answer:

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Explanation:

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4 years ago

The rate of reaction is fastest at the _______ of a chemical reaction

astraxan [27]

Answer:

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Explanation:

Reactions can be followed by measuring changes in concentration, mass and volume of reactants or products. The rate is highest at the start of the reaction because the concentration of reactants is highest at this point.

Hope this helped! :^)

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The pressure at a point on a sloping surface within a tank filled with liquid depends on the

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A. height of the liquid above the point

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