Question

If the magnitude of a charge is twice as much as another charge, but the force experienced is the same, then the electric field strength of this charge is _____ the strength of the other charge.

Answer 1

Answer:

The new electric field strength of this charge is half of the strength of the other charge.

Explanation:

The electric force acting on the charge particle is given by :

F = q E

$E=\dfrac{F}{q}$

Where

q is the charged particle

E is the electric field

If the magnitude of a charge is twice as much as another charge, q' = 2q, but the force experienced is the same, then the new electric field is given by :

$E'=\dfrac{F}{q'}$

$E'=\dfrac{F}{(2q)}$

$E'=\dfrac{1}{2}\times \dfrac{F}{q}$

$E'=\dfrac{E}{2}$

So, the new electric field strength of this charge is half of the strength of the other charge. Hence, this is the required solution.