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choli [55]
3 years ago
6

Football player A has a mass of 210 pounds and is running at a rate of 5.0mi/hr. He collides with player B. Player B has a mass

of 190 pounds and is running in the same direction at 3.0 mi/hr. Which of the following statements is true?
A.) The momentum before the collision is equal to the momentum after the collision.
B.) The momentum before the collision is greater than the momentum after the collision.
C.) The momentum before the collision is less than the momentum after the collision.
Physics
2 answers:
LuckyWell [14K]3 years ago
8 0
The answer is b.) the momentum before the collision is greater than the momentum after the collision
NikAS [45]3 years ago
8 0

Answer: A.) The momentum before the collision is equal to the momentum after the collision.

Explanation:

From the Law of conservation of momentum, in a closed system, the net momentum is conserved.

Be it elastic collision or inelastic collision, whenever there is no external force acting in a system, the net momentum is always conserved.

Thus, initial momentum before collision is equal to the final momentum after collision.

Correct option is A.

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Answer:

6.49 x 10^-8 N

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dalvyx [7]
(a) The electrons move horizontally from west to east, while the magnetic field is directed downward, toward the surface. We can determine the direction of the force on the electron by using the right-hand rule:
- index finger: velocity --> due east
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- thumb: force --> due north
However, we have to take into account that the electron has negative charge, therefore we have to take the opposite direction: so, the magnetic force is directed southwards, and the electrons are deflected due south.

b) From the kinetic energy of the electrons, we can find their velocity by using
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v= \sqrt{ \frac{2K}{m} }= \sqrt{ \frac{2 \cdot 2.20 \cdot 10^{-15} J}{9.1 \cdot 10^{-31} kg} }=6.95 \cdot 10^7 m/s

The Lorentz force due to the magnetic field provides the centripetal force that deflects the electrons:
qvB = m \frac{v^2}{r}
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By re-arranging the equation, we find the radius r:
r= \frac{mv}{qB}= \frac{(9.1 \cdot 10^{-31} kg)(6.95 \cdot 10^7 m/s)}{(1.6 \cdot 10^{-19} C)(3.00 \cdot 10^{-5} T)}=13.18 m

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