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choli [55]
3 years ago
6

Football player A has a mass of 210 pounds and is running at a rate of 5.0mi/hr. He collides with player B. Player B has a mass

of 190 pounds and is running in the same direction at 3.0 mi/hr. Which of the following statements is true?
A.) The momentum before the collision is equal to the momentum after the collision.
B.) The momentum before the collision is greater than the momentum after the collision.
C.) The momentum before the collision is less than the momentum after the collision.
Physics
2 answers:
LuckyWell [14K]3 years ago
8 0
The answer is b.) the momentum before the collision is greater than the momentum after the collision
NikAS [45]3 years ago
8 0

Answer: A.) The momentum before the collision is equal to the momentum after the collision.

Explanation:

From the Law of conservation of momentum, in a closed system, the net momentum is conserved.

Be it elastic collision or inelastic collision, whenever there is no external force acting in a system, the net momentum is always conserved.

Thus, initial momentum before collision is equal to the final momentum after collision.

Correct option is A.

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kati45 [8]

Explanation:

Drinking water requirement in town 2.0 m^3/s of water per second

nitrate in local well  nitrate per 15 \mathrm{m}^{3} of water

nitrate in distant reservoir =5 \mathrm{~g} / \mathrm{m}^{3}

Let the flow rate of well

flow rate of reservoir =y m^{3} / s

Drinking water requirement is 45 \mathrm{ppm} or 45 \mathrm{~g} / \mathrm{m}^{3}

therefore, the total flow of drinking water

 

8 0
3 years ago
a body dropped from a height reaches a velocity of 13m/s just before touching the ground. What is the initial height of the ball
SashulF [63]

Hi there!

We can use the following (derived) equation to solve for the final velocity given height:

vf = √2gh

We can rearrange to solve for height:

vf² = 2gh

vf²/2g = h

Plug in the given values (g = 9.81 m/s²)

(13)²/2(9.81) = 8.614 m

We can calculate time using the equation:

vf = vi + at, where:

vi = initial velocity (since dropped from rest, = 0 m/s)

a = acceleration (in this instance, due to gravity)

Plug in values:

13 = at

13/a = t

13/9.81 = 1.325 sec

5 0
2 years ago
The position of a particle is given by ~r(t) = (3.0 t2 ˆi + 5.0 ˆj j 6.0 t kˆ) m
Julli [10]

Answer:

v=(6ti+6k)\ m/s

Explanation:

Given that,

The position of a particle is given by :

r(t) = (3.0 t^2 i + 5.0j+ 6.0 tk) m

Let us assume we need to find its velocity.

We know that,

v=\dfrac{dr}{dt}\\\\=\dfrac{d}{dt}(3.0 t^2 i + 5.0j+ 6.0 tk) \\\\=(6ti+6k)\ m/s

So, the velocity of the particle is (6ti+6k)\ m/s.

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3 years ago
A car starts from rest and speeds up to 30 m/s in a total of 6 s.
sveta [45]
5 m/s
30 divided by 6 is 5
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2 years ago
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viktelen [127]
You divide 72 by 12 to get 6.
8 0
3 years ago
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