Answer:
4.767 grams of KCl are produced from 2.50 g of K and excess Cl2
Explanation:
The balanced equation is
2 K+ Cl2 --->2 KCI
Here the limiting agent is K. Hence, the amount of KCl will be calculated as per the mass of 2.50 gram of K
Mass of one atom/mole of potassium is 39.098 grams
Number of moles is 2.5 grams = 
So, 2 moles of K produces 2 moles of KCL
0.064 moles of K will produces 0.064 moles of KCl
Mass of one molecule of KCl is 74.5513 g/mol
Mass of 0.064 moles of KCl is 4.767 grams
Answer is D.
Among the given options, the products of equation A, B and C are aqueous solutions. Those are indicated by using (aq).
The balanced equation for the reaction between Li₂CO₃(aq) and FeCl₂(aq) is Li₂CO₃(aq) + FeCl₂(aq) → 2LiCl(aq) + FeCO₃(s)
LiCl is a salt while FeCO₃ is a Grey/green color precipitate. Hence, option D represents a precipitation reaction.
By definition of conjugated and non-conjugated acids, Conjugate acids<span> are a type of acid that gains a proton in solution in response to a base that has happily accepted a proton.
</span><span>
This how the compounds are to be sorted.
</span>-butanoic acid<span>
-but-2-enoic acid
</span>-hexan-3-one<span>
-hex-4-en-3-one
</span>
B. she can ask people about their backgrounds
This requires listening, the rest do not
