Find the age t of a sample, if the total mass of carbon in the sample is mc, the activity of the sample is a, the current ratio
of the mass of 14 6c to the total mass of carbon in the atmosphere is r, and the decay constant of 14 6c is λ. assume that, at any time, 14 6c is a negligible fraction of the total mass of carbon and that the measured activity of the sample is purely due to 14 6c. also assume that the ratio of mass of 14 6c to total carbon mass in the atmosphere (the source of the carbon in the sample) is the same at present and on the day when the number of 14 6c atoms in the sample was set. express your answer in terms of the mass ma of a 14 6c atom, mc, a, r, and λ.
N₀ is the number of C-14 atoms per kg of carbon in the original sample at time = Os when its carbon was of the same kind as that present in the atmosphere today. After time ts, due to radioactive decay, the number of C-14 atoms per kg of carbon is the same sample which has decreased to N. λ is the radioactive decay constant. Therefore N = N₀e-λt which is the radioactive decay equation, N₀/N = eλt In (N₀.N= λt. This is the equation 1 The mass of carbon which is present in the sample os mc kg. So the sample has a radioactivity of A/mc decay is/kg. r is the mass of C-14 in original sample at t= 0 per total mass of carbon in a sample which is equal to [(total number of C-14 atoms in the sample at t m=m 0) × ma]/ total mass of carbon in the sample. Now that the total number of C-14 atoms in the sample at t= 0/ total mass of carbon in sample = N₀ then r = N₀×ma So N₀ = r/ma. this equation 2. The activity of the radioactive substance is directly proportional to the number of atoms present at the time. Activity = A number of decays/ sec = dN/dt = λ(number of atoms of C-14 present at time t) = λ₁(N×mc). By rearranging we get N = A/(λmc) this is equation 3. By plugging in equation 2 and 3 and solve t to get t = 1/λ In (rλmc/m₀A).
They may be at a similar latitude. But you also have to consider the currents nearby the location.
The prevailing wind closer to the equator which carries warm current hits Hillsdale which is why it follows the coastline of the continent. However, for Cordera prevailing winds carrying cold currents hits the continent and follows or hits the coastline of Cordera.
When an electric current is passed through acidified water, it decomposes to give hydrogen and oxygen gas. The hydrogen gas is obtained at the cathode and the oxygen gas is obtained at the anode
A, a heterogeneous mixture is a mixture where all the particles are not made up of one uniform composition. you can distinguish the different particles
