Question

What is the molarity of a solution that contains 87.75g of NaCI in 500.ml of solution

Answer 1

Answer:

M = 3.0 mol/L.

Explanation:

• We can calculate the molarity of a solution using the relation:

M = (mass x 1000) / (molar mass x V)

• M is the molarity "number of moles of solute per 1.0 L of the solution.

• mass is the mass of the solute (g) (m = 87.75 g of NaCl).

• molar mass of NaCl = 58.44 g/mol.

• V is the volume of the solution (ml) (V = 500.0 ml).

∴ M = (mass x 1000) / (molar mass x V) = (87.75 g x 1000) / (58.44 g/mol x 500.0 ml) = 3.0 mol/L.