Answer:
Total pressure 5.875 atm
Explanation:
The equation for above decomposition is
rate constant 
Half life 
Initial pressure 
Pressure after 3572 min = P
According to first order kinematics
solving for P we get
P = 2.35 atm
initial 4.70 0 0
change -2x +2x +x
final 4.70 -2x 2x x
pressure of
after first half life = 2.35 = 4.70 - 2x
x = 1.175
pressure of 
after first half life = 2x = 2(1.175) = 2.35 ATM
Total pressure = 2.35 + 2.35 + 1.175
= 5.875 atm
I think the answer is [Xe] 6s2
Answer:
78.3 × 10²³ atoms of helium are present in 52 g.
Explanation:
Given data:
Mass of He = 52 g
Number of atoms = ?
Solution:
First of all we will calculate the number of moles of He
Number of moles = mass /molar mass
Number of moles = 52 g/ 4 g/mol
Number of moles = 13 mol
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
1 mole = 6.022 × 10²³ atoms of helium
13 mol × 6.022 × 10²³ atoms of helium / 1 mole
78.3 × 10²³ atoms of helium
Answer:
Mass of oxygen required = 19.5 moles × 16 g/mol = 312 g.
Explanation:
