Question

A gas expands from an initial volume of 30.0 L to a final volume of 65.0 L at a constant pressure of 110kPa. How much work is done by the gas?

Answer 1

Answer:

3850 J

Explanation:

$V_{i}$ = initial volume of the gas = 30 L = 0.03 m³

$V_{f}$ = final volume of the gas = 65 L = 0.065 m³

$P$ = Constant pressure of the gas = 110 kPa = 110000 Pa

$W$ = Work done by the gas

Since the pressure is constant, Work done by the gas is given as

$W = P (V_{f} - V_{i})\\W = (110000) (0.065 - 0.03)\\W = 3850 J$