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Pachacha [2.7K]
4 years ago
12

A gas expands from an initial volume of 30.0 L to a final volume of 65.0 L at a constant pressure of 110kPa. How much work is do

ne by the gas?
Physics
1 answer:
Brilliant_brown [7]4 years ago
8 0

Answer:

3850 J

Explanation:

V_{i} = initial volume of the gas = 30 L = 0.03 m³

V_{f} = final volume of the gas = 65 L = 0.065 m³

P = Constant pressure of the gas = 110 kPa = 110000 Pa

W = Work done by the gas

Since the pressure is constant, Work done by the gas is given as

W = P (V_{f} - V_{i})\\W = (110000) (0.065 - 0.03)\\W = 3850 J

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Katarina [22]

Answer:

The induced current is 26.7 mA

Explanation:

Given;

area of the loop, A = 0.078 m²

initial magnetic field, B₁ = 3.8 T

change in the magnetic field strength, dB/dt = 0.24 T/s

The induced emf is calculated as;

emf = - \frac{d \phi}{dt} \\\\emf = -\frac{dB.A}{dt} \\\\emf = A (\frac{dB}{dt} )\\\\emf = 0.078(0.24)\\\\emf = 0.0187 \ V

The resistance of the loop = 0.7 Ω

The induced current is calculated as;

V = IR\\\\I = \frac{V}{R} = \frac{emf}{R} = \frac{0.0187}{0.7} = 0.0267 \ A = 26.7 \ mA

4 0
3 years ago
The roller coaster from problem #1 then tops a second hill at 15.0 m/s, how high is the second hill?
navik [9.2K]

Answer:

68.5

Explanation:

4 0
3 years ago
In a displacement/time graph the slope of the line is equal to the ________.
mamaluj [8]
In a displacement/time graph, the slope of the line is equal to the velocity
3 0
3 years ago
What happens to the rock structure during each of type of change?
EastWind [94]
Previous rocks melt and collide and to form igneous rocks.
Igneous rocks disintegrate due to weather disruptions and get carried away by water, where they form sedimentary rock strata by lithification.
Igneous and sedimentary change by heat and pressure to form metamorphic rocks.
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3 0
3 years ago
A spy satellite uses a telescope with a 1.7-m-diameter mirror. It orbits the earth at a height of 180 km.
WINSTONCH [101]

Answer: the minimum spacing that must be there between two objects on the earth's surface if they are to be resolved as distinct objects by this telescope 6.45 cm

Explanation:

Given that;

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wavelength λ = 500 nm = 5 × 10⁻⁹ m

Now Angular separation from the peak of the central maximum is expressed as;

sin∅= 1.22 λ / d

sin∅ = (1.22 × 5 × 10⁻⁹) / 1.7

 sin∅ = 3.588 × 10⁻⁷

we know that;

 sin∅  = object separation / distance from telescope

object separation =   sin∅ × distance from telescope

object separation = 3.588 × 10⁻⁷  × 180 × 10³

object separation =6.45 × 10⁻² m

then we convert to centimeter

object separation = 6.45 cm

Therefore the minimum spacing that must be there between two objects on the earth's surface if they are to be resolved as distinct objects by this telescope 6.45 cm

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3 years ago
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