1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Pachacha [2.7K]
3 years ago
12

A gas expands from an initial volume of 30.0 L to a final volume of 65.0 L at a constant pressure of 110kPa. How much work is do

ne by the gas?
Physics
1 answer:
Brilliant_brown [7]3 years ago
8 0

Answer:

3850 J

Explanation:

V_{i} = initial volume of the gas = 30 L = 0.03 m³

V_{f} = final volume of the gas = 65 L = 0.065 m³

P = Constant pressure of the gas = 110 kPa = 110000 Pa

W = Work done by the gas

Since the pressure is constant, Work done by the gas is given as

W = P (V_{f} - V_{i})\\W = (110000) (0.065 - 0.03)\\W = 3850 J

You might be interested in
Differences between <br>hor<br>rse<br>and horse​
kenny6666 [7]
The proper difference between hor Rse and horse is both shows the same thing that is the horse
5 0
3 years ago
Read 2 more answers
An 20-cm-long Bicycle Crank Arm. With A Pedal At One End. Is Attached To A 25-cm-diameter Sprocket, The Toothed Disk Around Whic
malfutka [58]

To solve the problem, it is necessary to apply the concepts related to the kinematic equations of the description of angular movement.

The angular velocity can be described as

\omega_f = \omega_0 + \alpha t

Where,

\omega_f =Final Angular Velocity

\omega_0 =Initial Angular velocity

\alpha = Angular acceleration

t = time

The relation between the tangential acceleration is given as,

a = \alpha r

where,

r = radius.

PART A ) Using our values and replacing at the previous equation we have that

\omega_f = (94rpm)(\frac{2\pi rad}{60s})= 9.8436rad/s

\omega_0 = 63rpm(\frac{2\pi rad}{60s})= 6.5973rad/s

t = 11s

Replacing the previous equation with our values we have,

\omega_f = \omega_0 + \alpha t

9.8436 = 6.5973 + \alpha (11)

\alpha = \frac{9.8436- 6.5973}{11}

\alpha = 0.295rad/s^2

The tangential velocity then would be,

a = \alpha r

a = (0.295)(0.2)

a = 0.059m/s^2

Part B) To find the displacement as a function of angular velocity and angular acceleration regardless of time, we would use the equation

\omega_f^2=\omega_0^2+2\alpha\theta

Replacing with our values and re-arrange to find \theta,

\theta = \frac{\omega_f^2-\omega_0^2}{2\alpha}

\theta = \frac{9.8436^2-6.5973^2}{2*0.295}

\theta = 90.461rad

That is equal in revolution to

\theta = 90.461rad(\frac{1rev}{2\pi rad}) = 14.397rev

The linear displacement of the system is,

x = \theta*(2\pi*r)

x = 14.397*(2\pi*\frac{0.25}{2})

x = 11.3m

5 0
3 years ago
The kinetic energy of a 1000-kg roller coaster car that is moving with a speed of 20.0 m/s.
eimsori [14]
E=(mV^2)/2
m=1000kg, V=20m/s
then, E=(1000kg*(20m/s)^2)/2
E=(1000*400)/2 J = 200000J
8 0
3 years ago
If the angular velocity of the pully is -8.4rad/s at a given time, and its anglar acceleration is -2.8rad/s2, what is the angula
snow_lady [41]

Here we know that

\omega_i = - 8.4 rad/s

\alpha = - 2.8 rad/s^2

t = 1.5 s

now from kinematics we have

\omega_f = \omega_i + \alpha t

now from above all values we have

\omega_f = (-8.4 rad/s) + (-2.8 rad/s^2)(1.5)

\omega_f = -8.4 + (-4.2)

\omega_f = -12.6 rad/s

so final angular speed is -12.6 rad/s

6 0
3 years ago
The SI unit for energy is Newton true or false
ipn [44]

Explanation:

false....it is joules

..........

6 0
2 years ago
Other questions:
  • A golfer starts with the club over her head and swings it to reach maximum speed as it contacts the ball. Halfway through her sw
    5·1 answer
  • Assume that a magnetic field exists and its direction is known. Then assume that a charged particle moves in a specific directio
    10·1 answer
  • Does high pressure rise and low pressure sink
    9·2 answers
  • I will Mark Brainliest 1. ) Allena and Charissa were discussing whether Cl2 is an element or a compound. Allena said that it is
    13·1 answer
  • Lots of points and brainiest for first correct answer
    8·1 answer
  • Which statement best describes perigee?
    6·1 answer
  • An average force of 328 N acts for a time interval of 0.05s on a golf ball
    9·1 answer
  • Paul is driving his car on a sunny afternoon. Which glasses should he ideally wear while driving?
    14·1 answer
  • Calculate the total resistance in the circuit​
    7·2 answers
  • A block with a mass of 1kg moving at a velocity of 3m/s collides and sticks to a block of mass of 4kg initially at rest. What is
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!