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3 years ago

11

The burner on a stove is 325° f. given that the burner emits electromagnetic radiation as a blackbody, what is the maximum wavel

ength of the emitted light spectrum?

1 answer:

lesantik [10]3 years ago

5 0

To solve this, we use the Wien's Displacement Law as shown in the attached picture. First, convert the temperature to Kelvin.

C to F:
C = (F - 32)*5/9
C = (325 - 32)*5/9 = 162.78 °C

C to K:
K = C + 273
K = 162.78 + 273 = 435.78 K

λmax = 2898/435.78 = <em>6</em><em>.65 μm</em>

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A long, thin straight wire with linear charge density λ runs down the center of a thin, hollow metal cylinder of radius R. The c

Delvig [45]

Answer:

$E=\dfrac{\lambda }{2\pi \varepsilon _or}$

Explanation:

Given that

For straight wire

Charge density= λ

For hollow metal cylinder

Charge density=2 λ

We know that electric filed for wire given as

$E_w=\dfrac{\lambda_{wire} }{2\pi \varepsilon _or}$

$E_w=\dfrac{\lambda }{2\pi \varepsilon _or}$

Now the electric filed due to hollow metal cylinder

$E_c=\dfrac{\lambda_{cylinder} }{2\pi \varepsilon _or}$

$E_c=\dfrac{2\lambda }{2\pi \varepsilon _or}$

Now by considering the Gaussian surface r<R then only electric fild due to wire will present.So

At r<R

$E=\dfrac{\lambda }{2\pi \varepsilon _or}$

5 0

4 years ago

A tub of water is placed in a small room and heat is removed from the room. What will most likely occur if enough heat is remove

NARA [144]

Answer:

(A)The water will freeze.

Explanation:

Heat is the energy that when transferred causes change in temperature. If heat is added to a body by some process the bodies temperature increases and if heat is removed from a body by some process the temperature reduces.

In this case if enough heat is removed from the room the internal movement of the water particles will slow down causing the water to form crystal lattice thus forming ice. So, the water will freeze.

6 0

3 years ago

Read 2 more answers

The primary job of a(n) ____ <br> is to increase the power of a modified radio wave.

amm1812

The primary job of a(n) ____

is to increase the power of a modified radio wave.

Answer:

<h2>amplifier</h2>

Explanation:

Hope it helps:)

#CarryOnLearning

4 0

3 years ago

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Suppose the rocket in the Example was initially on a circular orbit around Earth with a period of 1.6 days. Hint (a) What is its

ruslelena [56]

Answer:

a

The orbital speed is $v= 2.6*10^{3} m/s$

b

The escape velocity of the rocket is $v_e= 3.72 *10^3 m/s$

Explanation:

Generally angular velocity is mathematically represented as

$w = \frac{2 \pi}{T}$

Where T is the period which is given as 1.6 days = $1.6 *24 *60*60 = 138240 sec$

Substituting the value

$w = \frac{2 \pi}{138240}$

$= 4.54*10^ {-5} rad /sec$

At the point when the rocket is on a circular orbit

The gravitational force = centripetal force and this can be mathematically represented as

$\frac{GMm}{r^2} = mr w^2$

Where G is the universal gravitational constant with a value $G = 6.67*10^{-11}$

M is the mass of the earth with a constant value of $M = 5.98*10^{24}kg$

r is the distance between earth and circular orbit where the rocke is found

Making r the subject

$r = \sqrt[3]{\frac{GM}{w^2} }$

$= \sqrt[3]{\frac{6.67*10^{-11} * 5.98*10^{24}}{(4.45*10^{-5})^2} }$

$= 5.78 *10^7 m$

The orbital speed is represented mathematically as

$v=wr$

Substituting value

$v= (5.78*10^7)(4.54*10^{-5})$

$v= 2.6*10^{3} m/s$

The escape velocity is mathematically represented as

$v_e = \sqrt{\frac{2GM}{r} }$

Substituting values

$= \sqrt{\frac{2(6.67*10^{-11})(5.98*10^{24})}{5.78*10^7} }$

$v_e= 3.72 *10^3 m/s$

7 0

3 years ago

At room temperature, sound travels at a speed of about 344 m/s in air. You see a distant flash of lightning and hear the thunder

bearhunter [10]

Answer:

<em>The lighten travels 0.853 miles.</em>

Explanation:

Sound: Sound is a form of wave which is conveyed through an elastic medium from a vibrating body to a listener.

v = 2x/t .......................................... Equation 1

making x the subject of the equation

x = vt/2........................................ Equation 2

Where v = velocity of sound in air, x = distance traveled by the sound, t = time

Given: v = 344 m/s t = 8 s

Substituting into equation 2

x = 344(8)/2

x = 1376 m.

x = 1376×0.00062 miles = 0.853 miles

<em>Thus the lighten travels 0.853 miles.</em>

4 0

3 years ago

Read 2 more answers