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3 years ago

Sand dunes during the Dust Bowl are an example of:

Physics

1 answer:

choli [55]3 years ago

5 0

Sand dunes during the Dust Bowl are an example of windward.

The sand dunes are formed due to high movement of wind in the deserts which make dunes in the direction where wind is moving. Windward refers to facing the wind or situated on the side facing the wind so in those regions where the wind moves bring sand with itself and make dunes in that area so we can conclude that sand dunes are formed in the windward regions.

Learn more: brainly.com/question/24879138

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The field inside a charged parallel-plate capacitor is __________.

Bess [88]

<span>Uniform. A parallel plate capacitor is a simple arrangement of electrodes and dielectric to form a capacitor. Here two parallel conductive plates are used as electrodes with a medium or dielectric in between them. Charge separation in a parallel-plate capacitor causes an internal electric field, which is uniform.</span>

5 0

4 years ago

Read 2 more answers

1. Use Newton's first law of motion to explain how wearing a seat belt in a moving car could help prevent injury

hjlf

The diver is plummiting to earth and if he does not put it soon he is going to die

4 0

3 years ago

What is the total energy q released in a single fusion reaction event for the equation given in the problem introduction? use c2

kkurt [141]

Answer:

$4.3\cdot 10^{-12} J$

Explanation:

The fusion reaction in this problem is

$4^1_1H \rightarrow ^4_2He +2e^+$

The total energy released in the fusion reaction is given by

$\Delta E = c^2 \Delta m$

where

$c=3.0\cdot 10^8 m/s$ is the speed of light

$\Delta m$ is the mass defect, which is the mass difference between the mass of the reactants and the mass of the products

For this fusion reaction we have:

$m(^1_1H)=1.007825u$ is the mass of one nucleus of hydrogen

$m(^4_2 He)=4.002603u$ is the mass of one nucleus of helium

So the mass defect is:

$\Delta m =4m(^1_1 H)-m(^4_2 He)=4(1.007825u)-4.002603u=0.028697u$

The conversion factor between atomic mass units and kilograms is

$1u=1.66054\cdot 10^{-27}kg$

So the mass defect is

$\Delta m =(0.028697)(1.66054\cdot 10^{-27})=4.765\cdot 10^{-29}kg$

And so, the energy released is:

$\Delta E=(3.0\cdot 10^8)^2(4.765\cdot 10^{-29})=4.3\cdot 10^{-12} J$

6 0

3 years ago

Question 2 (1 point)

love history [14]

Answer:

neutral

Explanation:

3p - 3e = 0 and that leaves 2 neutrons so it will be neutral

6 0

4 years ago

Read 2 more answers

Earth has a mass of 5.97 × 1024 kg and a radius of 6.38 × 106 m, while Saturn has a mass of 5.68 × 1026 kg and a radius of 6.03

hammer [34]

Answer: mass on earth = 625.792 N, mass on saturn = 666.75 N

Explanation: weight of an object = mg

Where g = acceleration due to gravity =GM/r²

Where G = gravitational constant, M = mass of planet and r = radius of planet.

Let us start with earth.

G =gravitational constant of the earth =6.67×10^-11 m³ /kgs²

Me = mass of earth = 5.97×10^24 kg

re = radius of earth = 6.38×10^6 m

Acceleration due to gravity on earth = (6.67×10^-11×5.97×10^24) /(6.38×10^6)²

Acceleration due to gravity on earth = 3.98×10^14 /4.07×10^13

Acceleration due gravity on earth = 9.778 m/s²

The mass of the person is 64 kg, hence his weight on earth is given as

W = mass × Acceleration due gravity on earth = 64 ×9.778 = 625.792 N

For saturn.

G =gravitational constant of the earth =6.67×10^-11 m³ /kgs²

Ms = mass of saturn = 5.68×10^26kg

rs= radius of saturn= 6.03×10^7 m

Acceleration due to gravity on saturn= (6.67×10^-11×5.68×10^26 /(6.03×10^7)²

Acceleration due to gravity on saturn= 3.788×10^16/3.636×10^15

Acceleration due gravity on saturn= 10.417 m/s²

The mass of the person is 64 kg, hence his weight on saturn is given as

W = mass × Acceleration due gravity on saturn = 64 ×10.417 = 666.75 N

3 0

3 years ago