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3 years ago

A ball is thrown upward with an initial velocity of 12.1 m/s. How long will it take to reach a velocity of -24.5 m/s?

Physics

1 answer:

Rainbow [258]3 years ago

5 0

<h3><u>Answer;</u></h3>

= 3.73 seconds

<h3><u>Explanation;</u></h3>

Using the equation;

v = u + at

where v is the final velocity, u is the initial velocity and a is the acceleration due to gravity (-g) and t is the time taken.

Therefore;

v = u - gt

Thus;

v = 24.5 m/s, u = 12.1 m/s, a = -g = 9.8 m/s²

-24.5 m/s = 12.1 - 9.8 × t

36.6 = 9.8 t

t = 36.6/9.8

= 3.73 seconds

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3 years ago

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Answer:

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Explanation:

Given that

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$D=\dfrac{\sqrt{l^2+b^2}}{lb}$

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3 years ago

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3 years ago

Read 2 more answers

How much work does the electric field do in moving a proton from a point with a potential of +125 v to a point where it is -55 v

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The work W done by the electric field in moving the proton is equal to the difference in electric potential energy of the proton between its initial location and its final location, therefore:
$W= qV_i - qV_f$
where q is the charge of the proton, $q=1 e = 1.6\cdot 10^{-19}C$ , with $e$ being the elementary charge, and $V_i = +125 V$ and $V_f = -55 V$ are the initial and final voltage.

Substituting, we get (in electronvolts):
$W=e(125 V-(-55 V))=180 eV$
and in Joule:
$W=(1.6 \cdot 10^{-19})(125 V-(-55V))=2.88 \cdot 10^{-17}J$

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3 years ago