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3 years ago

How many types of progression in mathematics?

1 answer:

3 0

There are three different type

Explain

In math , there are three different type , they are arithmetic progression ( Ap) , Geometric progression and Harmonic

Arithmetic Progression - When a fix constant is added to each number except the first number.

For example : 2,4,6,8,10..... Here 2 is added each time to get the next number.

2. Geometric Progression - When a fix constant is multiplied to each number except the first number.

For example : 2,6,18,54.... Here 3 is multiplies each time to get first number.

3. Harmonic - a harmonic progression (or harmonic sequence) is a progression formed by taking the reciprocals of an arithmetic progression.

For example : 1/2 , 1/4 , 1/6, 1/8 ....

You might be interested in

makvit [3.9K]

Answer:

This is the form

Where

is the slope and the

value is the y-intercept

First plot the

value in this case it is -5

Then from that point

(

−

)

use the slope to find the other points

Rise translates to the amount of units "up or down" you go

Up = Positive

Down = Negative

Run translates to the amount of units "left or right" you go

Left = Negative

Right = Positive

So starting from the point

(

−

)

go up 4 units and right 1 unit or down 4 and left 1 unit since they both make the slope of 4 -->

(

)

and

(

−

)

I hope that is a better answer

Step-by-step explanation:

Plz brainliest

6 0

4 years ago

Read 2 more answers

A store is having a 20% off sale. The sale price of an item with price p is p – 0.2p. What is an equivalent expression?

GuDViN [60]

If it is 20% off, then ur actually paying 80%
so an equivalent expression would be 0.80p

3 0

3 years ago

Read 2 more answers

Find equations of the spheres with center(3, −4, 5) that touch the following planes.a. xy-plane b. yz- plane c. xz-plane

postnew [5]

Answer:

(a) (x - 3)² + (y + 4)² + (z - 5)² = 25

(b) (x - 3)² + (y + 4)² + (z - 5)² = 9

Step-by-step explanation:

The equation of a sphere is given by:

(x - x₀)² + (y - y₀)² + (z - z₀)² = r² ---------------(i)

Where;

(x₀, y₀, z₀) is the center of the sphere

r is the radius of the sphere

Given:

Sphere centered at (3, -4, 5)

=> (x₀, y₀, z₀) = (3, -4, 5)

(a) To get the equation of the sphere when it touches the xy-plane, we do the following:

i. Since the sphere touches the xy-plane, it means the z-component of its centre is 0.

Therefore, we have the sphere now centered at (3, -4, 0).

Using the distance formula, we can get the distance d, between the initial points (3, -4, 5) and the new points (3, -4, 0) as follows;

$d = \sqrt{(3-3)^2+ (-4 - (-4))^2 + (0-5)^2}$

$d = \sqrt{(3-3)^2+ (-4 + 4)^2 + (0-5)^2}$

$d = \sqrt{(0)^2+ (0)^2 + (-5)^2}$

$d = \sqrt{(25)}$

d = 5

This distance is the radius of the sphere at that point. i.e r = 5

Now substitute this value r = 5 into the general equation of a sphere given in equation (i) above as follows;

(x - 3)² + (y - (-4))² + (z - 5)² = 5²

(x - 3)² + (y + 4)² + (z - 5)² = 25

Therefore, the equation of the sphere when it touches the xy plane is:

(x - 3)² + (y + 4)² + (z - 5)² = 25

(b) To get the equation of the sphere when it touches the yz-plane, we do the following:

i. Since the sphere touches the yz-plane, it means the x-component of its centre is 0.

Therefore, we have the sphere now centered at (0, -4, 5).

Using the distance formula, we can get the distance d, between the initial points (3, -4, 5) and the new points (0, -4, 5) as follows;

$d = \sqrt{(0-3)^2+ (-4 - (-4))^2 + (5-5)^2}$

$d = \sqrt{(-3)^2+ (-4 + 4)^2 + (5-5)^2}$

$d = \sqrt{(-3)^2 + (0)^2+ (0)^2}$

$d = \sqrt{(9)}$

d = 3

This distance is the radius of the sphere at that point. i.e r = 3

Now substitute this value r = 3 into the general equation of a sphere given in equation (i) above as follows;

(x - 3)² + (y - (-4))² + (z - 5)² = 3²

(x - 3)² + (y + 4)² + (z - 5)² = 9

Therefore, the equation of the sphere when it touches the yz plane is:

(x - 3)² + (y + 4)² + (z - 5)² = 9

(b) To get the equation of the sphere when it touches the xz-plane, we do the following:

i. Since the sphere touches the xz-plane, it means the y-component of its centre is 0.

Therefore, we have the sphere now centered at (3, 0, 5).

Using the distance formula, we can get the distance d, between the initial points (3, -4, 5) and the new points (3, 0, 5) as follows;

$d = \sqrt{(3-3)^2+ (0 - (-4))^2 + (5-5)^2}$

$d = \sqrt{(3-3)^2+ (0+4)^2 + (5-5)^2}$

$d = \sqrt{(0)^2 + (4)^2+ (0)^2}$

$d = \sqrt{(16)}$

d = 4

This distance is the radius of the sphere at that point. i.e r = 4

Now substitute this value r = 4 into the general equation of a sphere given in equation (i) above as follows;

(x - 3)² + (y - (-4))² + (z - 5)² = 4²

(x - 3)² + (y + 4)² + (z - 5)² = 16

Therefore, the equation of the sphere when it touches the xz plane is:

(x - 3)² + (y + 4)² + (z - 5)² = 16

3 0

3 years ago

A person gets on and off a bathroom scale four times. The four readings (in pounds) are 148, 151, 150, and 152. Each time after

Ganezh [65]

Answer:

See explanation below

Step-by-step explanation:

Since each time after the person gets off the scale, the reading is 2 lb the person's weight must be near the mean of

148-2, 151-2, 150-2, 152-2; that is to say, near the mean of 146, 149, 148, 150 = (146+149+148+150)/4 = 148.25

We could estimate the uncertainty as the standard error SE

$\bf SE=\frac{s}{\sqrt{n}}$

where

s = standard deviation of the sample

n = 4 sample size.

Computing s:

$\bf s=\sqrt{\frac{(146-148.25)^2+(149-148.25)^2+(148-148.25)^2+(150-148.25)^2}{4}}=1.479$

So, the uncertainty is 1.479/2 = 0.736

It is not possible to estimate the bias, since it is the difference between the true weight and the mean, but we do not know the true weight.

5 0

3 years ago

60 What is the sum of the series E3n?

wariber [46]

Answer:

B, 2,010

Hope this helps have a nice day/night :)

6 0

3 years ago

Read 2 more answers

How many types of progression in mathematics?​

How many types of progression in mathematics?