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icang [17]
3 years ago
13

A submarine dives to a depth of 100-m beneath the surface of the Pacific Ocean. The density of sea water is 1030 kg/m3. The subm

arine has a hatch with an area of 2 m2 located on the top of the submarine. No need to show work. a) Calculate the gauge pressure applied on the submarine at the depth of 100 m. b) Calculate the absolute pressure applied on the submarine at the depth of 100 m. Assume the atmospheric pressure in the air above the ocean is one atmosphere. c) Calculate how much force is required in order to open the hatch from the inside of submarine. Assume that the pressure inside the submarine is one atmosphere.
Physics
1 answer:
kozerog [31]3 years ago
6 0

Answer:

A) 1010430 pa

B) 1111755 pa

C) 2020860 N

Explanation:

Guage pressure = pgh

= 1030 kg/m3 x 9.81 m/s2 x 100 m

= 1010430 pa

Absolute pressure is Guage pressure + atmospheric pressure.

= 1010430 + 101325 = 1111755 pa

If the pressure inside submarine is 1 atm, then net pressure will be

1111755 - 101325 = 1010430 pa

Force required to open hatch against this pressure will be,

F = pghA

pgh = 1010430 pa

F = 1010430 pa x 2 m^2

F = 2020860 N

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kotykmax [81]

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Explanation:

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When a normal eye is at rest, parallel rays from a distant object are focused on the retina. The ability of the eye - lens to focus points at different distances on the retina is known as accomodation. The adjustment of the eye lens to focus objects of varying distances is brought about by the ciliary muscles. The have the ability to change the shape of the eye which leads to change in focal length.

When a person with normal vision looks at a distant object at infinity, the lens brings parallel rays to focus on the retina. Thus, the furthest point which the eye can see distinctly is called the far point of the eye and it's infinity for a normal eye. But Joe was able to focus his eye on the tree, meaning that the tree was within his near point. This is the nearest point at which an object is clearly seen. Therefore, when the effective focal length of the cornea-lens system changes, it changes the location of the image of any object in one's field of view.

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3 years ago
Explain why the model of this chemical reaction obeys the Law of Conservation of Matter. A) because there are the same number of
Sav [38]

Answer:

(A) because there are the same number of atoms of each element shown on both sides

Explanation:

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In a chemical reaction, while atoms bond is breaking of 1 substance than new bonds are formed in another substance and new substances are formed. However, in the overall reaction, they keep the same elements, no new elements can go and come from the outside. For example:

HCl + NaOH -----> NaCl + H2O

In this reaction, on both sides the same number of atoms of each element are present.

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elena55 [62]

Weight = (mass) x (acceleration of gravity at the place where the mass is) .

Man's mass = 80 kg

His weight on Earth = (80 kg) x (9.8 m/s²) = 784 newtons (about 176 pounds)

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His mass is <em>80 kg</em>.  Mass is the thing about him that doesn't change. 
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8 0
3 years ago
How to find out the heat capacity of a material?​
DochEvi [55]

\huge\underline{\underline{\boxed{\mathbb {EXPLANATION}}}}

The heat capacity is given by the expression:

\longrightarrow \sf{\triangle Q= m \triangle C  \triangle   T}

\longrightarrow \sf{Q= \: Heat}

\longrightarrow \sf{M= \: Mass}

\longrightarrow \sf{C= \: Specific \: Heat}

\longrightarrow \sf{T= \: Temperature}

\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}

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5 0
1 year ago
A golf ball strikes a hard, smooth floor at an angle of 28.2 ° and, as the drawing shows, rebounds at the same angle. The mass o
WITCHER [35]

Answer:

    I = 1.06886  N s

Explanation:

The expression for momentum is

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therefore the momentum is a vector quantity, for which we define a reference system parallel to the floor

Let's find the components of the initial velocity

          sin 28.2 = v_y / v

          cos 28.2=  vₓ / v

          v_y = v sin 282

          vₓ = v cos 28.2

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          vₓ = 42.8 cos 28.2 = 37.72 m / s

since the ball is heading to the ground, the vertical velocity is negative and the horizontal velocity is positive, it can also be calculated by making

θ = -28.2

         v_y = -20.55 m / s

         v_x = 37.72 m / s

X axis

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since the ball moves in the x-axis without changing the velocity, the change in moment must be zero

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therefore

          Iₓ = 0

Y axis  

        I_y = Δp_y = p_{fy} -p_{oy}

when the ball reaches the floor its vertical speed is downwards and when it leaves the floor its speed has the same modulus but the direction is upwards

         v_{fy} = - v_{oy}

         Δp_y = 2 m v_{oy}

         Δp_y = 2 0.0260 (20.55)

         \Delta p_{y} = 1.0686 N s

the total impulse is

          I = Iₓ i ^ + I_y j ^

          I = 1.06886  j^ N s

7 0
2 years ago
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