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icang [17]
3 years ago
13

A submarine dives to a depth of 100-m beneath the surface of the Pacific Ocean. The density of sea water is 1030 kg/m3. The subm

arine has a hatch with an area of 2 m2 located on the top of the submarine. No need to show work. a) Calculate the gauge pressure applied on the submarine at the depth of 100 m. b) Calculate the absolute pressure applied on the submarine at the depth of 100 m. Assume the atmospheric pressure in the air above the ocean is one atmosphere. c) Calculate how much force is required in order to open the hatch from the inside of submarine. Assume that the pressure inside the submarine is one atmosphere.
Physics
1 answer:
kozerog [31]3 years ago
6 0

Answer:

A) 1010430 pa

B) 1111755 pa

C) 2020860 N

Explanation:

Guage pressure = pgh

= 1030 kg/m3 x 9.81 m/s2 x 100 m

= 1010430 pa

Absolute pressure is Guage pressure + atmospheric pressure.

= 1010430 + 101325 = 1111755 pa

If the pressure inside submarine is 1 atm, then net pressure will be

1111755 - 101325 = 1010430 pa

Force required to open hatch against this pressure will be,

F = pghA

pgh = 1010430 pa

F = 1010430 pa x 2 m^2

F = 2020860 N

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larisa86 [58]

Answer:  

a) the magnitude of r is  184.62

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Explanation:

Given the data in the question;

as illustrated in the image blow;

To find the the magnitude of r, we will use the Pythagoras theorem

r² = y² + x²

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we substitute

r = √((-113)² + (-146)²)

r = √(12769 + 21316 )

r = √(34085 )

r = 184.62

Therefore, the magnitude of r is  184.62

To find its direction, we need to find ∅

from SOH CAH TOA

tan = opposite / adjacent

tan∅ = -113 / -146

tan∅ = 0.77397

∅ = tan⁻¹( 0.77397 )

∅ = 37.74°

Therefore, the direction is 37.74° south of the negative x-axis

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Eating an orange enables a person to perform about 3.5x10^4 J of work. To what height does eating and orange enable a 55kg woman
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Joules is a unit for work which may decomposed into N.m. Work is a quantity which is a product of force (in this case, the woman's weight) and the distance she has traveled. 
 
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Substituting the given, 
  
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3 0
3 years ago
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Heat energy moves:_______.
steposvetlana [31]

c) only from warmer areas to colder areas.

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A planetâs moon revolves around the planet with a period of 39 Earth days in an approximately circular orbit of radius of 4.8Ã10
Alchen [17]

Answer:

v = 895 m/s

Explanation:

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v = 895 m/s

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