Answer:
a) V ≈ 125 m/s; b) Δt = 13.24 s; c) ΔS ≈ 1450 m
Explanation:
a) We have just to calculate the vector resultant.
V² = 106² + 66.2²
V² = 15618.44
V ≈ 125 m/s
b) The time of flight is equal to the time to reach the maximum height summed to the time to reach the land.
In vertical:
V = V₀ + a * t
V = 66.2 - g * t
0 = 66.2 - 9.8 * t
t ≈ 6.76 s
So: Δt = 13.24 s
c) In horizontal:
V = ΔS / Δt
106 = ΔS / 13.52 ⇒ ΔS = 106 * 13.52
ΔS = 106 * 13.52
ΔS = 1433,12
ΔS ≈ 1450 m
Answer: 0.512 kgm²
Explanation:
Given
Force, F = 2*10^3 N
Angular acceleration, α = 121 rad/s²
Lever arm, r(⊥) = 3.1 cm = 3.1*10^-2 m
τ = r(⊥) * F
Also,
τ = Iα
Using the first equation, we have
τ = r(⊥) * F
τ = 0.031 * 2*10^3
τ = 62 Nm
Now we calculate for the inertia using the second equation
τ = Iα, making I subject of formula, we have
I = τ / α, on substituting, we have
I = 62 / 121
I = 0.512 kgm²
Thus, the moment of inertia of the boxers forearm is 0.512 kgm²
A fire because you feed it wood, it lives longer but if you give it a drink, water, then it dies.
Answer:
The volume of the cavity is 0.013m^3
Explanation:
To find the volume of the cavity, the major parameter missing is the diameter of the cavity itself. we can obtain this using the following steps:
Step one:
Obtain the volume of the cylinder by dividing the mass of the cylinder by the density.
Volume of the cylinder = 2.1 / 11.053 =0.19
Step two:
From the volume of the cylinder, we can get the radius of the cylinder.

Step three:
From the cross-sectional area, we can obtain the radius of the cavity.
Let the radius of the cavity be = r, while the radius of the cylinder be = R
CSA of cavity =

Step Four:
calculate the volume of the cavity using volume =
Recall that the cavity has the same height as the original cylinder

The displacement is 2 m south
Explanation:
Distance and displacement are two different quantities:
- Distance is the total length of the path covered by an object during its motion, regardless of the direction. It is a scalar quantity
- Displacement is a vector connecting the initial position to the final position of motion of an object. The magnitude of the displacement is the distance in a straight line between the two points
For the car in this problem, the motion is:
10 m south
8 m north
Taking north as positive direction, we can describe the two parts of the motion as

m
Therefore, the final position of the car with respect to the original position is

which means 2 m south: so, the displacement of the car is 2 m south.
Learn more about distance and displacement:
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