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elixir [45]
4 years ago
5

How long does it take for an obituary to appear?

Physics
2 answers:
Licemer1 [7]4 years ago
6 0
24hours is the correct answer
ozzi4 years ago
4 0
<span>If they have to do an autopsy then it can take a while (week) otherwise if he died late on Sept 5th then it would take probably 2 days before the notice would be in the Obits. Other than that you can go to the web sites of Funeral homes in the area where he lived and look up the death notices and he should be on there. Did you try all of the newspapers in your area. Just go on line to save time. Some families are so shocked at the death that they don't publish it until later or have a quiet funeral with immediate family and then after have a memorial where anyone can speak about the decease.</span>
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A 2.03 kg book is placed on a flat desk. Suppose the coefficient of static friction between the book and the desk is 0.442 and t
photoshop1234 [79]

Answer:

a) 8.80 N

b) 4.78 N

Explanation:

The weight of the book is

W = mg = 2.03\times9.81 = 19.9143 \text{ N}

By Newton's third law, the reaction from the table, R, is equal to its weight.

R = 19.9143 N

From the law of solid friction,

F = \mu R

F is the maximum frictional force and \mu is the coefficient of friction.

a) The force needed to begin moving the book is that needed to overcome static friction

F = 0.442\times19.9143 = 8.80\text{ N}

b) The force needed to move the book at constant speed once it begins moving is that needed to overcome kinetic friction

F = 0.240\times19.9143 = 4.78\text{ N}

8 0
3 years ago
Can someone explain to me what Murphy's law is and how it works?
Vikki [24]
<span>Murphy's law is an adage or epigram that is typically stated as: Anything that can go wrong, will go wrong.
</span><span>

</span>
3 0
4 years ago
When a sound wave moves past a point inair, what happens to the density of air at thispoint?1.There is no change in the density
Westkost [7]

Answer:

2.The density of air increases and thendecreases as the sound wave passes.

Explanation:

Sound waves are mechanical waves, which consist of oscillation of the particles in the medium where the wave is transmitted through.

Sound waves are also longitudinal waves, which means that the direction of oscillations of the particles of the medium occurs in a direction parallel to the direction of motion of the wave (so, essentially back and forth).

Due to the nature of longitudinal waves, they create alternating regions of the medium where the density of particles are higher and lower. The former are called compressions, while the latter are called rarefactions.

Therefore, when a sound wave travels through the air, the density of one region of air continuously changes: compression first (high density), rarefaction then (lower density), then compression again, etc..

8 0
3 years ago
Find the average velocity of the car during the time last three second interval. Answer in units of m/s.
Pani-rosa [81]

Answer:

<u>Average Velocity:</u>

When a body covers some displacement moving from point A to B, in a given time,t. Then dividing the total distance covered by the time taken to complete the displacement is called as the average velocity of that car.

We can calculate the average velocity of car by subtracting the initial displacement of a body,s₁ from  the final displacement position of the body, s₂. And then dividing by the initial time,t₁ been subtracted from the final time,t₂.

  • Δv=x₂-x₁/t₂-t₁,

We will get the required results, now if we want to obtain the results in the final three seconds then, we can have the following explanation to that as given.

Explanation:

Lets say, that we have the car moving for 10 seconds and then it stops at the eleventh second of the trip on final position, of the displacement. Then we divide the whole trips into small segments, as we will have the different velocity at each interval but, the velocity is unknown at the last 3 seconds is unknown=?.  

  • Total time taken, Δt= 11 seconds,
  • Then lets say the velocity at the 8th second is , v=25 m/s,then
  • Δv=x₂-(25)/11-0,⇒Δv=x₂-25/11,
3 0
3 years ago
Doc Brown has calculated his Delorean can accelerate at a rate of 2.52 m/s/s. How
GREYUIT [131]

Answer:

304.89m

Explanation:

Given

acceleration a = 2.52m/s²

final speed v = 39.2m/s

initial speed = 0m/s (car accelerates from rest)

Using the equation of motion below to get the distance of Doc brown from Marty;

v² = u²+2as

substitute the given parameters

39.2² = 0²+2(2.52)s

1536.64 = 0+5.04s

divide both sides by 5.04

1536.64/5.04 = 5.04s/5.04

rearrange the equation

5.04s/5.04 = 1536.64/5.04

s = 304.89m

Hence He and Marty must stand at 304.89m to allow the car to accelerate from rest to a speed  of 39.2 m/s?

6 0
4 years ago
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