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julsineya [31]
2 years ago
7

If you feed 100 kg of N2 gas and 100 kg of H2 gas into a reactor. What is the limiting reactant?

Chemistry
1 answer:
mixas84 [53]2 years ago
8 0

Answer:

N₂ is the limiting reactant

Explanation:

The balanced reaction between N₂ gas and H₂ gas is:

N₂ + 3H₂ → 2NH₃

In order to determine the limiting reactant, we have to <u>calculate the number of moles of each rectant</u>, using their molecular weight:

  • Moles of N₂= 100 kg * \frac{1kmol}{28kg} = 3.57 kmol
  • Moles of H₂= 100 kg * \frac{1kmol}{2kg} = 50.0 kmol

Lastly, we multiply the number of moles of N₂ by 3, and the number of moles of H₂ by 1; due to the coefficients in the balanced reaction. Whichever number is lower, belongs to the limiting reactant.

N₂ => 10.7

H₂ => 50.0

Thus N₂ is the limiting reactant

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Which of the following is a limitation of Bohr's model?
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2 years ago
What mass of sucrose needs to be dissolved in 540 g of water in order to prepare a 15% by mass solution.
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Answer:

95.3g

Explanation:

Given parameters:

Mass of water  = 540g

Percentage by mass of solution = 15%

Unknown:

Mass of sucrose = ?

Solution;

To solve this problem, we must understand that a solution is made up of solute dissolved in a solvent. A solute is the solid dissolved in another. The solvent is the is dissolving medium;

    Percentage by mass of solute in solution = \frac{Mass of solute}{Mass of solution}  x 100

Mass of solution  = mass of water + Mass of sucrose  = 540 + M

  where M is the mass of sucrose;

therefore;

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How many moles are in 23.4 g
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Explanation:

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Read 2 more answers
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