If you feed 100 kg of N2 gas and 100 kg of H2 gas into a reactor. What is the limiting reactant?
1 answer:
Answer:
N₂ is the limiting reactant
Explanation:
The balanced reaction between N₂ gas and H₂ gas is:
N₂ + 3H₂ → 2NH₃
In order to determine the limiting reactant, we have to <u>calculate the number of moles of each rectant</u>, using their molecular weight:
- Moles of N₂= 100 kg *
= 3.57 kmol
- Moles of H₂= 100 kg *
= 50.0 kmol
Lastly, we multiply the number of moles of N₂ by 3, and the number of moles of H₂ by 1; due to the coefficients in the balanced reaction. Whichever number is lower, belongs to the limiting reactant.
N₂ => 10.7
H₂ => 50.0
Thus N₂ is the limiting reactant
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Answer:
The correct answer to the following question will be "90.6 kJ/mol".
Explanation:
The total reactant solution will be:
The produced energy will be:
The reaction will be:
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Going to look at just the amounts of reactions with the same concentrations, we notice that they're really comparable.
Therefore, the moles generated by NaCl will indeed be:
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