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3 years ago

Which is a heterogeneous mixture a jar of nuts

Chemistry

1 answer:

pogonyaev3 years ago

6 0

Answer:

a party mix:-) it would be a jar of cashews, peanuts, almonds, ettc.

Explanation:

if you can separate the nuts, it is heterogenous

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Which list BEST identifies how the arrows should be arranged around the paper leaf in the model to represent the movement of mat

Andrew [12]

Answer:

D. Point into Leaf: water(H₂O), carbon dioxide (CO₂) sunlight, Point away from leaf: Sugars, oxygen (O₂)

Explanation:

Photosynthesis is the process used in the production of chemical energy in the form of energy containing organic compounds and oxygen from atmospheric carbon dioxide and liquid water enabled with the energy captured from light (mainly Sunlight) by the chlorophyll in green plants and other organisms

The basic chemical reaction involved in a photosynthesis reaction is presented as follows;

${}$ Sunlight

${}$ ↓

${}$ CO₂ + H₂O (l) → C₆H₁₂O₆ + O₂

Carbon dioxide ${}$ Water Glucose Oxygen

8 0

3 years ago

3 points

Strike441 [17]

Answer:

cần 162,5

Explanation:

100gKNO3 cần 1 mol kno3 từ đó suy ra cần 0,5 mol hg(no3)2 suy ra cần 162,5g hg(no3)2

8 0

3 years ago

Compute the molar enthalpy of combustion of glucose (C6 H12O6 ): C6 H12O6 (s) + 6 O2 (g) → 6 CO2 (g) + 6 H2 O (g) Given that com

lana66690 [7]

Answer:

The molar enthalpy of combustion of glucose is -2819.3 kJ/mol

Explanation:

Step 1: Data given

Mass of glucose = 0.305 grams

Combustion of 0.305 grams causes a raise of 6.30 °C

Calorimeter has a heat capacity of 755 J/°C

Molar mass of glucose = 180.2 g/mol

Step 2: The balanced equation

C6H12O6 (s) + 6O2 (g) → 6CO2 (g) + 6H2O (g)

Step 3:

ΔH = (m * C * ΔT + c(calorimeter) * ΔT)

with m = mass of the solutin = 0.305 grams

with C = heat capacity of water = 4.184 J/g°C

with ΔT = the change in temperature = 6.30 °C

with c(calorimeter) = 755 J/°C

ΔH = 0.305 * 4.184 *6.30 + 755 * 6.30 = 4764.5 J ( negative because it's exothermic)

Step 4: Calculate moles of glucose

Moles glucose = mass glucose / Molar mass glucose

Moles glucose = 0.305 grams / 180.2 g/mol

Moles glucose = 0.00169 moles

Step 5: Calculate molar enthalpy

Molar enthalpy = -4764.5 J / 0.00169 moles

Molar enthalpy = - 2819254.2 J/moles = -2819.3 kJ/moles

The molar enthalpy of combustion of glucose is -2819.3 kJ/mol

5 0

3 years ago

Saturated hydrocarbons are generally unreactive except in the presence of _____.

Citrus2011 [14]

Hello!

Saturated hydrocarbons are generally unreactive except in the presence of high temperatures and oxygen.

Saturated hydrocarbons are called Alkanes. These compounds are generally unreactive, but when exposed to high temperatures and oxygen they react in a combustion reaction to produce Carbon Dioxide and Water. This reaction is very violent and spontaneous and explosions of household gas cylinders occur because of the spontaneity of this reaction.

Have a nice day!

6 0

3 years ago

How many moles of oxygen must be placed

umka21 [38]

Answer: 0.245 moles of oxygen must be placed in the container to exert the given pressure at the given temperature. The Ideal Gas Law equation gives the relationship among the pressure, volume, temperature, and moles of gas.

Further Explanation:

The Ideal Gas Equation is:

$PV = nRT$