Which is a heterogeneous mixture a jar of nuts

A gas has a pressure of 1.34 atm when the temperature is 237K. The gas is then

Naddika [18.5K]

Answer:

$\large \boxed{\text{1.76 atm}}$

Explanation:

The volume and amount of gas are constant, so we can use Gay-Lussac’s Law:

At constant volume, the pressure exerted by a gas is directly proportional to its temperature.

$\dfrac{p_{1}}{T_{1}} = \dfrac{p_{2}}{T_{2}}$

Data:

p₁ = 1.34 atm; T₁ = 237 K

p₂ = ?; T₂ = 312 K

Calculations:

$\begin{array}{rcl}\dfrac{1.34}{237} & = & \dfrac{p_{2}}{312}\\\\5.654 \times 10^{-3} & = & \dfrac{p_{2}}{312}\\\\5.654 \times 10^{-3}\times312&=&p_{2}\\p_{2} & = & \textbf{1.76 atm}\end{array}\\\text{The new pressure will be $\large \boxed{\textbf{1.76 atm}}$}$

6 0

3 years ago

Yellow light has a frequency of 5.2 × 1014 Hz and travels at a speed of 3.0 × 108 m/s. What is the wavelength of yellow light, i

mina [271]

Answer:

5750 angstrong unit to 5850 angstrong unit

5 0

3 years ago

Match the action to the effect on the equilibrium position for the reaction N2(g) + 3H2(g) ⇌ 2NH3(g). Match Term Definition Incr

KIM [24]

Answer:

1) Increasing the pressure C) Shift to the right

2) Removing hydrogen gas A) Shift to the left

3) Adding a catalyst B) No effect

Explanation:

Le Châtelier's principle states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.

1) Increasing the pressure:

When there is an increase in pressure, the equilibrium will shift towards the side with fewer moles of gas of the reaction. And when there is a decrease in pressure, the equilibrium will shift towards the side with more moles of gas of the reaction.

The reactants side (left) has 4.0 moles of gases and the products side (right) has 2.0 moles of gases.

So, increasing the pressure will shift the reaction to the side with lower moles of gas (right side).

so, the right match is: C) Shift to the right.

2) Removing hydrogen gas:

Removing hydrogen gas will decrease the concentration of the products side, so the reaction will be shifted to the lift side to suppress the decrease in the concentration of hydrogen gas by removing.

so, the right match is: A) Shift to the left.

3) Adding a catalyst:

Catalyst increases the rate of the reaction without affecting the equilibrium position.

Catalyst increases the rate via lowering the activation energy of the reaction.

This can occur via passing the reaction in alternative pathway (changing the mechanism).

The activation energy is the difference in potential energies between the reactants and transition state (for the forward reaction) and it is the difference in potential energies between the products and transition state (for the reverse reaction).

in the presence of a catalyst, the activation energy is lowered by lowering the energy of the transition state, which is the rate-determining step, catalysts reduce the required energy of activation to allow a reaction to proceed and, in the case of a reversible reaction, reach equilibrium more rapidly.

with adding a catalyst, both the forward and reverse reaction rates will speed up equally, which allowing the system to reach equilibrium faster.

so, the right match is: B) No effect.

4 0

3 years ago

Four difference between electrolytic cell and electrochemical cell

luda_lava [24]

Answer:

Electrochemical cells convert chemical energy into electrical energy or vice versa. Electrolytic cell is a type of electrochemical cell in which electrical energy is converted into chemical energy. ... Electrolytic cells consist of positively charged anode and a negatively charged cathode.

I hope it's help

3 0

3 years ago

A chemist adds of a iron(III) bromide solution to a reaction flask. Calculate the mass in kilograms of iron(III) bromide the che

vaieri [72.5K]

Answer:

0.246 kg

Explanation:

There is some info missing. I think this is the original question.

A chemist adds 370.0mL of a 2.25 M iron(III) bromide (FeBr₃) solution to a reaction flask. Calculate the mass in kilograms of iron(III) bromide the chemist has added to the flask. Be sure your answer has the correct number of significant digits.

We have 370.0 mL of 2.25 M iron(III) bromide (FeBr₃) solution. The moles of FeBr₃ are:

0.3700 L × 2.25 mol/L = 0.833 mol

The molar mass of iron(III) bromide is 295.56 g/mol. The mass corresponding to 0.833 moles is:

0.833 mol × 295.56 g/mol = 246 g

1 kilogram is equal to 1000 grams. Then,

246 g × (1 kg/1000 g) = 0.246 kg

3 0

4 years ago