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3 years ago

15

Quadratic equations that can be solved using the quadratic formula can also be solved by factoring. ...?

1 answer:

valina [46]3 years ago

5 0

I believe the correct answer is false. Quadratic equations that can be solved using the quadratic formula cannot always be solved by factoring. <span>Not </span>all quadratic equations can<span> be </span>solved by factoring<span>. Another method that can be used is completing the square. Hope this answers the question.</span>

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Find three consecutive odd integers such that three times the sum of the first and second is 3 more than 3 times the third

Rufina [12.5K]

Answer:

3, 5, 7

Step-by-step explanation:

1st number: (2k+1)

2nd number: (2k+3)

3rd number: (2k+5), k∈Z

3*[(2k+1) + (2k+3)] = 3 + 3*(2k+5)

3*(4k+4)=3+6k+15

12k+12=18+6k

6k=6

k=1

1st number: (2k+1) = 3

2nd number: (2k+3)=5

3rd number: (2k+5)=7

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3 years ago

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tigry1 [53]

Answer:

$\tan(J) =\frac{5\sqrt{66}}{66}$

Step-by-step explanation:

$\tan(J) =\frac{5}{\sqrt{66}}$

$\tan(J) =\frac{5}{\sqrt{66}} \times \frac{\sqrt{66}}{\sqrt{66}}$

$\tan(J) =\frac{5\sqrt{66}}{\sqrt{66}\times\sqrt{66} }$

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3 years ago

Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (

Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

$P(\frac{T}{S}) = 0.95$

$P(\frac{T}{S^c}) = 0.05$

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

$P(S^c) = 1 - P(S)$

= 1 - 0.3

= 0.7

ii. $P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}$

$= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }$

$= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}$

= 0.8906

iii. $P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}$

$= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }$

$= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}$

= 0.0221

We simply applied the above formulas so that the each part could come

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3 years ago

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vagabundo [1.1K]

Answer:

Both are equations, one is linear, one is not linear boom

Step-by-step explanation:

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Nostrana [21]

Europe. And just so you know this should have been under a different topic.

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