8.66mls = v1
vf2 = vi2 + a(d)
(0mls) squared = visquared + - 5mls squared (15m)
0mls squared = vi2 - 75m squared / s squared

75 m squared/s squared = vi
Hope this helps!
Answer:
I've always wanted to be a nurse. growing up my auntie used to show me a lot of stuff about becoming a nurse since she us one.
Answer:
0.0021576N
Explanation:
F=(k)(q1q2/r^2)
F=(8.99×10^9)(3×10^-6)(2×10^-6)/(5^2)
F=0.0021576N
Answer:
20 N/m
Explanation:
From the question,
The ball-point pen obays hook's law.
From hook's law,
F = ke............................ Equation 1
Where F = Force, k = spring constant, e = compression.
Make k the subject of the equation
k = F/e........................ Equation 2
Given: F = 0.1 N, e = 0.005 m.
Substitute these values into equation 2
k = 0.1/0.005
k = 20 N/m.
Hence the spring constant of the tiny spring is 20 N/m