Question

A centrifuge in a medical laboratory rotates at an angular speed of 3,400 rev/min. When switched off, it rotates through 52.0 revolutions before coming to rest.
Find the constant angular acceleration (in rad/s2) of the centrifuge.


______rad/s2

Answer 1

The constant angular acceleration (in rad/s2) of the centrifuge is 194.02 rad/s².

Constant angular acceleration

Apply the following kinematic equation;

ωf² = ωi² - 2αθ

where;

• ωf is the final angular velocity when the centrifuge stops = 0
• ωi is the initial angular velocity
• θ is angular displacement
• α is angular acceleration

ωi = 3400 rev/min x 2π rad/rev x 1 min/60s = 356.05 rad/s

θ = 52 rev x 2π rad/rev = 326.7 rad

0 = ωi² - 2αθ

α = ωi²/2θ

α = ( 356.05²) / (2 x 326.7)

α = 194.02 rad/s²

Thus, the constant angular acceleration (in rad/s2) of the centrifuge is 194.02 rad/s².

Learn more about angular acceleration here: brainly.com/question/25129606

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