A centrifuge in a medical laboratory rotates at an angular speed of 3,400 rev/min. When switched off, it rotates through 52.0 re
volutions before coming to rest.
Find the constant angular acceleration (in rad/s2) of the centrifuge.
______rad/s2
Find the constant angular acceleration (in rad/s2) of the centrifuge.
______rad/s2
1 answer:
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Answer:
The answer is 2,416 m/s. Let's jump in.
Explanation:
We do work with the amount of energy we can transfer to objects. According to energy theory:
W = ΔE
Also as we know W = F.x
We choose our reference point as a horizontal line at the block's rest point.<u> At the rest, block doesn't have kinetic energy</u> and <u>since it is on the reference point(as we decided) it also has no potential energy.</u>
Under the force block gains;
W = F.x →
In the second position block has both kinetic and potential energy. Following the law of conservation of energy;
W = ΔE = Kinetic energy + Potantial Energy
W = ΔE =
Here we can find h in the triangle i draw in the picture using sine theorem;
In a triangle
In our situation
→
Therefore
→
The angle of the pendulum with the vertical is
Explanation:
As the train decelerates, the bob of the pendulum will feel a force given by
where
m = 0.55 kg is the mass of the bob
is the magnitude of the acceleration
In the horizontal direction.
The pendulum will be inclined at an angle from the vertical, so it will be in equilibrium, and therefore the horizontal component of the tension in the string must be equal to the net force F of the previous equation:
(1)
where T is the tension in the string.
We also know that the bob is in equilibrium along the vertical direction: so the vertical component of the tension must be equal to the weight of the bob,
(2)
where is the acceleration of gravity.
Dividing eq.(1) by eq(2), we get:
And therefore, we find the angle:
Learn more about forces and acceleration:
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