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Ymorist [56]
3 years ago
6

What is acceleration due to gravity

Physics
2 answers:
rjkz [21]3 years ago
7 0
The acceleration developed between two bodies containing mass as a result of the gravitational force between them.
Studentka2010 [4]3 years ago
5 0
If you stay on the same planet and drop a lot of objects one at a time,
it turns out that every object you drop falls from your hand to the ground
with the same acceleration, and hits the ground with the same speed,
no matter whether the object is light, heavy, or anything in between.

That particular value of acceleration is the "acceleration due to gravity".
On Earth, it's 9.81 meters per second².  On the moon, it's 1.62 meters
per second².  On Jupiter, it's 25.89 meters per second².

Why we don't generally notice it:  The previous description is true if the
ONLY force on the object is the force of gravity.  If it has to fall through
<u>air</u> on the way down, then the air can have a great effect on it.  Many
museums have an exhibit where they drop things in a long tube with
all the air removed from it, and there you can see some pretty weird
stuff ... like a bowling ball, a rock, a sheet of paper, and a feather, all
falling together, with nothing fluttering.

<u>Why</u> everything falls with the same acceleration ?  That's a separate question.




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01:28:29
Novosadov [1.4K]

Answer:

an inverse relationship

7 0
3 years ago
If the sprinter accelerates at that rate for a distance of 15 m, and then maintains the velocity he has at that point for the re
ahrayia [7]

Answer:

The time for the entire race is 11.39 sec.

Explanation:

Given that,

Distance = 15 m

Remainder distance = 100 m

Suppose A sprinter begins a race with an acceleration of 3.4 m/s².

We need to calculate the time

Using equation of motion

s=ut+\dfrac{1}{2}at^2

Put the value in the equation

15=0+\dfrac{1}{2}\times3.4\times t^2

t^2=\dfrac{30}{3.4}

t=2.97\ sec

We need to calculate the final velocity of sprinter

Using equation of motion again

v=u+at

Put the value into the formula

v=0+3.4\times2.97

v=10.09\ m/s

We need to calculate the distance covers by sprinter

d=100-15=85\ m

The sprinter need to covers only 85 m.

We need to calculate the time

Using formula of time

t=\dfrac{d}{v}

Put the value into the formula

t'=\dfrac{85}{10.09}

t'=8.42\ sec

We need to calculate the time for the entire race

t''=t+t'

Put the value into the formula

t''=2.97+8.42

t''=11.39\ sec

Hence, The time for the entire race is 11.39 sec.

4 0
3 years ago
If the bar magnet is flipped over and the south pole is brought near the hanging ball, the ball will be?
disa [49]

The ball may attracted to the magnet.

<h3>How can we understand that the hanging ball will be attracted to the magnet or not?</h3>
  • From the question, we understand that the ball is attracted by the north pole of the bar magnet, then the bar magnet flipped over and the south pole is brought near the hanging ball.
  • As we know, in this type of experiments of bar magnet most of the times the ball is made out of steel.
  • Steel is a magnetic material.
  • Magnetic materials gets attracted  to the magnet at both the North and South pole.
  • This can be compared to how neutral objects also gets attracted to the positively and negatively charged rods through the Polarization force.

So, If the bar magnet is flipped over and the south pole is brought near the hanging ball, The ball will be attracted to the magnet.

Learn more about the bar magnet:

brainly.com/question/27943723

#SPJ4

7 0
1 year ago
Name the physical quantity which changes contenously during uniform-circular motion.
kumpel [21]
The direction of the motion is constantly changing during
motion over any closed path, not only circular.
8 0
3 years ago
Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 9.0 km/h due east. Runner B is initia
Eduardwww [97]

Answer:

From the data we know that runner A and runner B are 11 km apart from the start because (6+5) km

So the runner from the east direction has distance as unknown km, rate= 9 k/h ; time= d/r=x/9 hr

So runner towards the west will be

distance = 11-x, rate= 8 k/h, time = d/r = (11-x)/8

So equating east and west time we have

x/9= (11-x)/8

8x=99-9x

17x=99

x=5.92 km

That is the distance covered by runner towards the east and he will meet the runner toward the west at

6-5.92=0.08 km west of the flagpole.

7 0
3 years ago
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