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olchik [2.2K]
3 years ago
13

Una grúa con un motor de 10 CV eleva 1000 kg de hierro hasta

Physics
1 answer:
lora16 [44]3 years ago
6 0

Answer:

can u write in eng I didn't recognize your language...

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In a shipping yard, a crane operator attaches a cable to a 1240-kg shipping container and then uses the crane to lift the contai
Firdavs [7]

Answer:

Explanation:

Given

mass of ship =1240 kg

height=37 m

(a)Work done by Tension in cable+work done by gravity =0

Work done by gravity =change in potential energy of mass=-1240\times 9.8\times 37=-449.624 kJ

Thus work done by tension=449.624 kJ

(b)work done by force of gravity=-mg\times h=-1240\times 9.8\times 37=-449.624 kJ

4 0
3 years ago
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Hair sticking to a balloon after it<br> has been rubbed on a girl's head is<br> an example of
Lesechka [4]

Answer:

Friction

Explanation:

6 0
2 years ago
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Work is a transfer of (1 point) energy. force. mass. motion.
jok3333 [9.3K]
Energy is the ability to do work.

So work can not be done without the transfer of energy from one body to another.

Work is the transfer of energy.
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3 years ago
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The potential energy stored in the compressed spring of a dart gun, with a spring constant of 32.50 N/m, is 0.640 J. Find by how
liraira [26]

Answer:

A

   x = 0.198456 \ m

B

    h  =  1.3061 \  m

C

 v =  5.06 \  m/s

D

  d = 4.0273 \  m

Explanation:

Considering the first question

From the question we are told that

   The spring constant is  k  =  32.50 N/m

    The potential energy is  PE  =  0.640 \ J

Generally the potential  energy stored in spring  is mathematically represented as   PE  =  \frac{1}{2}  *  k  *  x^2

=>    0.640=  \frac{1}{2}  * 32.50  *  x^2  

=>    x = \sqrt{0.03938}  

=>    x = 0.198456 \ m  

Considering the second question

 From the question we are told that

   The mass of the dart is  m =  0.050 kg

Generally from the law of energy conservation

         PE =  mgh

=>       0.640   =  0.050 *  9.8  *  h

=>      h  =  1.3061 \  m

Considering the third  question

   The height at which the dart was fired horizontally is  H  =   3.90\  m

Generally  from the law of energy conservation

         PE = KE

Here  KE is kinetic energy of the dart which is mathematical represented as

     KE  =  \frac{1}{2}  *  mv^2

=>      0.640 =  \frac{1}{2}  * 0.050 *  v^2

=>       v^2 = 25.6

=>       v =  5.06 \  m/s

Considering the fourth question

Generally the total time of flight of the dart is mathematically represented as

       t  =  \frac{ 2 *  H }{g}

=>     t  =  \frac{ 2 * 3.90 }{9.8 }

=>     t  =  0.7959 \ s

Generally the  horizontal distance from the equilibrium position to the ground is  mathematically represented as

       d =  v  *   t

=>     d = 5.06  *   0.7959

=>     d = 4.0273 \  m

5 0
2 years ago
What us meant by Velocity ratio of simple machine is 4?<br><br><br>​
butalik [34]
The force ratio of a machine is 4 and it velocity ratio is 4 means that the load moved is four times the effort applied and the distance moved by the effort is five times the distance moved by the load at the same time interval.



Please mark as brainliest
8 0
3 years ago
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