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2 years ago

Una grúa con un motor de 10 CV eleva 1000 kg de hierro hasta

Physics

1 answer:

lora16 [44]2 years ago

6 0

Answer:

can u write in eng I didn't recognize your language...

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If a person pushes a box up a ramp, in which direction will the box exert a force on the person? up the ramp toward the person d

EleoNora [17]

Down the ramp toward the person

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2 years ago

Read 2 more answers

A 21 g ball is shot from a spring gun whose spring has a force constant of 579 N/m. The spring can be compressed 1 cm. How high

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Answer:

The answer to the question is

The ball will go 0.14 meters high if the gun is aimed vertically

Explanation:

The energy in the spring → Energy, E = $\frac{1}{2}kx^2$

Where E = energy in the spring

k = Spring constant

x = Spring compression or stretch

Therefore E = $\frac{1}{2} 579*0.01^2 = 0.02895 J$

The spring energy is transferred to the ball as kinetic energy based on the first law of thermodynamics which states that energy is neither created nor destroyed

Kinetic energy = KE = $\frac{1}{2}mv^2$

From which v = $\sqrt{\frac{2*KE}{m} }$ = $\sqrt{\frac{2*0.02895}{0.021} }$ = 1.66 m/s

from v² =u² - 2·a·S

Where v = final velocity = 0 m/s

u = initial velocity = 1.66 m/s

a = g = Acceleration due to gravity

S = height

Therefore 0 = 1.66² - 2×9.81×S

or S = 1.66² ÷ (2×9.81) = 0.14 m

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2 years ago

A 3.30-kg block starts from rest at the top of a 30.0° incline and slides a distance of 2.10 m down the incline in 1.60 s.(a) fi

AnnZ [28]

<span>Mass of the block m = 3.3kg Angle of the slide = 30 degrees Distance the block slides s = 2.10 m Time taken to slide t = 1.6 s Initially in rest condition so initial velocity u = 0. We have an equation for distance s = (u x t) + (1/2) x (a t^2) s = (0 x t) + (1/2) x (a x (1.6) ^2) => 2.10 = (1/2) x (a x2.56) 2.56a = 4.20 => a = 1.64 So the magnitude of the Acceleration a = 1.64 m/s^2</span>

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3 years ago

A cylinder containing the air comprises the systemm. Cycle is completed as follows : (i) 82000 N-m of work is done by the piston

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Answer & Explanation:

1 N-m = 1 Joule

So 82 kJ of energy put into the system during (i).

45 kJ of heat leaves the system, so 82 kJ - 45 kJ = 37 kJ is remaining.

(ii) requires 100 kJ of energy but only 37 kJ is available, so 100 kJ - 37 kJ = 63 kJ of heat energy must be added to the system.

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