Answer:
<em>If it served you, give me 5 stars please, thank you!</em>
<em />
<em>m = </em><u><em>25</em></u><em> </em><em> </em><u><em>Kg</em></u>
I think that should be evaporation :)
Answer:
The percent abundance of oxygen-18 is 1.9066%.
Explanation:
The average atomic mass of oxygen is given by:
![m_{O} = m_{^{16}O}*\%_{16} + m_{^{17}O}*\%_{17} + m_{^{18}O}*\%_{18}](https://tex.z-dn.net/?f=%20m_%7BO%7D%20%3D%20m_%7B%5E%7B16%7DO%7D%2A%5C%25_%7B16%7D%20%2B%20m_%7B%5E%7B17%7DO%7D%2A%5C%25_%7B17%7D%20%2B%20m_%7B%5E%7B18%7DO%7D%2A%5C%25_%7B18%7D%20)
Where:
m: is the atomic mass
%: is the percent abundance
Since the sum of the percent abundance of oxygen isotopes must be equal to 1, we have:
![1 = \%_{16} + \%_{17} + \%_{18}](https://tex.z-dn.net/?f=%201%20%3D%20%5C%25_%7B16%7D%20%2B%20%5C%25_%7B17%7D%20%2B%20%5C%25_%7B18%7D%20)
![1 = x + 3.2 \cdot 10^{-4} + \%_{18}](https://tex.z-dn.net/?f=%201%20%3D%20x%20%2B%203.2%20%5Ccdot%2010%5E%7B-4%7D%20%2B%20%5C%25_%7B18%7D%20)
![\%_{18} = 1 - x - 3.2 \cdot 10^{-4}](https://tex.z-dn.net/?f=%20%5C%25_%7B18%7D%20%3D%201%20-%20x%20-%203.2%20%5Ccdot%2010%5E%7B-4%7D%20)
Hence, the percent abundance of O-18 is:
![15.9982 = 15.972*x + 16.988*3.2 \cdot 10^{-4} + 17.970*(1 - 3.2 \cdot 10^{-4} - x)](https://tex.z-dn.net/?f=15.9982%20%3D%2015.972%2Ax%20%2B%2016.988%2A3.2%20%5Ccdot%2010%5E%7B-4%7D%20%2B%2017.970%2A%281%20-%203.2%20%5Ccdot%2010%5E%7B-4%7D%20-%20x%29)
Hence, the percent abundance of oxygen-18 is:
Therefore, the percent abundance of oxygen-18 is 1.9066%.
I hope it helps you!