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Nastasia [14]
3 years ago
14

A 0.10 M aqueous solution of sodium sulfate, Na2SO4, is a better conductor of electricity than a 0.10 M aqueous solution of sodi

um chloride, NaCl. Which of the following best explains this observation?

Chemistry
1 answer:
djyliett [7]3 years ago
8 0

Answer:

More moles of ions are present in a given volume of 0.10 M Na₂SO₄ than in the same volume of 0.10 M NaCl.

Explanation:

The question is complete and clear, however the wording suggests that this is a multiple-choice question. An example of the answer options is found in the annexed picture.

In the case of the picture, the answer is d. This is because 1 mol of Na₂SO₄, when dissolved in water, produces 3 moles of ions, two Na⁺ ions and one SO₄⁻² ion. While 1 mol of NaCl under the same conditions produces only two moles of ions. One Na⁺ and one Cl⁻.

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Answer:

22.8 L

Explanation:

Step 1: Given data

  • Moles of the gas (n): 1.35 mol
  • Pressure of the gas (P): 1.30 atm
  • Temperature (T): -6°C
  • Ideal gas constant (R): 0.0821 atm.L/mol.K

Step 2: Convert "T" to Kelvin

We will use the following expression.

K = °C + 273.15 = -6 + 273.15 = 267 K

Step 3: Calculate the volume of the gas

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T / P

V = 1.35 mol × (0.0821 atm.L/mol.K) × 267 K / 1.30 atm

V = 22.8 L

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The oxidation of butane is shown in the following picture. As it is a complete combustion, the products of this reaction are carbon dioxide and water.

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