A 0.10 M aqueous solution of sodium sulfate, Na2SO4, is a better conductor of electricity than a 0.10 M aqueous solution of sodi
um chloride, NaCl. Which of the following best explains this observation?
1 answer:
Answer:
More moles of ions are present in a given volume of 0.10 M Na₂SO₄ than in the same volume of 0.10 M NaCl.
Explanation:
The question is complete and clear, however the wording suggests that this is a multiple-choice question. An example of the answer options is found in the annexed picture.
In the case of the picture, the answer is d. This is because 1 mol of Na₂SO₄, when dissolved in water, produces 3 moles of ions, two Na⁺ ions and one SO₄⁻² ion. While 1 mol of NaCl under the same conditions produces only two moles of ions. One Na⁺ and one Cl⁻.
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Answer:
Explanation:
Hello,
In this case, given the acid, we can suppose a simple dissociation as:
Which occurs in aqueous phase, therefore, the law of mass action is written by:
That in terms of the change due to the reaction's extent we can write:
But we prefer to compute the Kb due to its exceptional weakness:
Next, the acid dissociation in the presence of the base we have:
Whose solution is which equals the concentration of hydroxyl in the solution, thus we compute the pOH:
Finally, since the maximum scale is 14, we can compute the pH by knowing the pOH:
Regards.