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Nastasia [14]
3 years ago
14

A 0.10 M aqueous solution of sodium sulfate, Na2SO4, is a better conductor of electricity than a 0.10 M aqueous solution of sodi

um chloride, NaCl. Which of the following best explains this observation?

Chemistry
1 answer:
djyliett [7]3 years ago
8 0

Answer:

More moles of ions are present in a given volume of 0.10 M Na₂SO₄ than in the same volume of 0.10 M NaCl.

Explanation:

The question is complete and clear, however the wording suggests that this is a multiple-choice question. An example of the answer options is found in the annexed picture.

In the case of the picture, the answer is d. This is because 1 mol of Na₂SO₄, when dissolved in water, produces 3 moles of ions, two Na⁺ ions and one SO₄⁻² ion. While 1 mol of NaCl under the same conditions produces only two moles of ions. One Na⁺ and one Cl⁻.

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Answer:

Ba²⁺(aq) + 2 NO₃⁻(aq) + 2 Rb⁺(aq) + 2 OH⁻(aq) = Ba(OH)₂(s) + 2 Rb⁺(aq) + 2NO₃⁻(aq)

Explanation:

Let's consider the molecular equation between barium nitrate and rubidium hydroxide to produce barium hydroxide and rubidium nitrate.

Ba(NO₃)₂(aq) + 2 RbOH(aq) = Ba(OH)₂(s) + 2 RbNO₃(aq)

The complete ionic equation includes all the ions and the molecular species.

Ba²⁺(aq) + 2 NO₃⁻(aq) + 2 Rb⁺(aq) + 2 OH⁻(aq) = Ba(OH)₂(s) + 2 Rb⁺(aq) + 2NO₃⁻(aq)

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1. What pressure would be exerted by 46.0grams of hydrogen gas placed into a 3.00 L container at
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Answer:

187.34 atm

Explanation:

From the question,

PV = nRT.................. Equation 1

Where P = Pressure, V = Volume, n = number of mole, R = molar gas constant, T = Temperature.

make P the subject of the equation

P = nRT/V.............. Equation 2

n = mass(m)/molar mass(m')

n = m/m'............... Equation 3

Substitute equation 3 into equation 2

P = (m/m')RT/V............ Equation 4

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