A 0.10 M aqueous solution of sodium sulfate, Na2SO4, is a better conductor of electricity than a 0.10 M aqueous solution of sodi
um chloride, NaCl. Which of the following best explains this observation?
1 answer:
Answer:
More moles of ions are present in a given volume of 0.10 M Na₂SO₄ than in the same volume of 0.10 M NaCl.
Explanation:
The question is complete and clear, however the wording suggests that this is a multiple-choice question. An example of the answer options is found in the annexed picture.
In the case of the picture, the answer is d. This is because 1 mol of Na₂SO₄, when dissolved in water, produces 3 moles of ions, two Na⁺ ions and one SO₄⁻² ion. While 1 mol of NaCl under the same conditions produces only two moles of ions. One Na⁺ and one Cl⁻.
You might be interested in
Answer : The volume of sodium benzoate and benzoic acid solution mixed to prepare this buffer should be, 29.0 mL and 71 mL respectively.
Explanation :
Let the volume of sodium benzoate (salt) be, x
So, the volume of benzoic acid (acid) will be, (100 - x)
Using Henderson Hesselbach equation :
Now put all the given values in this expression, we get:
x = 29.0
The volume of sodium benzoate = x = 29.0 mL
The volume of benzoic acid (acid) = (100 - x) = (100 - 29.0) = 71 mL
Thus, the volume of sodium benzoate and benzoic acid solution mixed to prepare this buffer should be, 29.0 mL and 71 mL respectively.