Answer:
it's B ;)
Step-by-step explanation:
A line segment has two endpoints; that is, it has a starting point and an ending point, much like a dead-end street. Bisector means to divide, not just in two, but in halves, or two equal parts. Therefore, a segment bisector is a point, a line, a ray, or a line segment that bisects another line segment.
Answer:
7.065 sq. cm
Step-by-step explanation:
Diameter= 3 cm
Since 2r=d, the radius is 1.5 cm
Circle area formula:
πr^2 --> 3.14(r^2)
Plug in r:
A=3.14(1.5^2)
A=3.14(2.25)
A=7.065
Ound your χ2 to three decimal places and round your P-value to four<span> decimal places.) 0. Ask for details; Follow · Report ... </span>Suppose<span> a </span>family stability measure<span> was </span>administered<span> in </span>four public high schools<span> to a </span>sample<span> of </span>24 students<span> who </span>attend<span> the </span>schools<span>. The </span>scores below<span> were obtained. Is there a difference in.</span>
You would use the formula for the specific term you wish to find;
The formula is:

a = starting value of the sequence
d = the common difference (i.e. the difference between any two consecutive terms of the sequence)
n = the value corresponding to the position of the desired term in the sequence (i.e. 1 is the first term, 2 is the second, etc.)
Un = the actual vaue of the the term
For example, if we have the arithmetic sequence:
2, 6, 10, 14, ...
And let's say we want to find the 62nd term;
Then:
a = 2
d = 4
(i.e. 6 - 2 = 4, 10 - 6 = 4, 14 - 10 = 4;
You should always get the same number no matter which two terms you find the difference between so long as they are both
consecutive [next to each other], otherwise you are not dealing with an arithmetic sequence)
n = 62
And so:
Answer:
The last equation x2 - 2x -4 = 0
has solution (x - 1)^2 - 5 = 0, x = 1 + root(5) or x = 1 - root(5)
Step-by-step explanation:
If a quadratic function has roots 1 and 5
f(x) = (x -1)(x- 5)
f(x) = x^2 - 6x + 5
Unless you meant. -4 and 6 ?
g(x) = (x + 4)(x - 6)
g(x) = x^2 -2x -24
-------------------------
Or did you mean x = 1 and x =4 ?...
x^2 + 2x + 4 = 0 : complete square x^2 + 2x + 1 + 3 = 0, (x+1)^2 + 3 = 0
x^2 - 2x + 4 = 0 : complete square: (x -1)^2 + 3 = 0
0x^2 + 2x - 4 = 0, 2x - 4 = 0, x = 2
x^2 - 2x - 4 = 0 becomes: x^2 - 2x + 1 - 1 -4 = 0 ; (x - 1)^2 - 5 = 0