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garri49 [273]
3 years ago
8

Latent heat is used to: 1. form chemical bonds. 2. change molecular structure. 3. change states of matter. 4. change the tempera

ture of a substance. 5. break chemical bonds.
Chemistry
1 answer:
likoan [24]3 years ago
7 0

Answer : The correct option is, (3) change states of matter.

Explanation :

Latent heat : It is defined as the heat required to convert the solid into liquid or vapor and a liquid into a vapor without changing the temperature.

There are two types of latent heat.

(1) Latent heat of fusion

(2) Latent heat of vaporization

Latent heat of fusion : It is defined as the amount of heat energy released or absorbed when the solid converted to liquid at atmospheric pressure at its melting point.

Latent heat of vaporization : It is defined as the amount of heat energy released or absorbed when the liquid converted to vapor at atmospheric pressure at its boiling point.

Hence, latent heat is used to change states of matter.

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Perform the following mathematical operation and then report the answer.
Kisachek [45]
The answer would be 833.7
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Complete the sentence. ______________ is thought to be most responsible for the salinity of the oceans.
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3 years ago
What is the balanced chemical equation for the reaction between aluminum and copper nitrate? Use this resource on polyatomic ion
abruzzese [7]
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3 0
3 years ago
Read 2 more answers
A 0.753 g sample of a monoprotic acid is dissolved in water and titrated with 0.250 M NaOH. What is the molar mass of the acid i
Alexeev081 [22]

Answer:

MM_{acid}=140.1g/mol

Explanation:

Hello,

In this case, since the acid is monoprotic, we can notice a 1:1 molar ratio between, therefore, for the titration at the equivalence point, we have:

n_{acid}=n_{base} \\\\V_{acid}M_{acid}=V_{base}M_{base}\\\\n_{acid}=V_{base}M_{base}

Thus, solving for the moles of the acid, we obtain:

n_{acid}=0.0215L*0.250\frac{mol}{L}=5.375x10^{-3}mol

Then, by using the mass of the acid, we compute its molar mass:

MM_{acid}=\frac{0.753g}{5.375x10^{-5}mol} \\\\MM_{acid}=140.1g/mol

Regards.

7 0
3 years ago
How much heat in joules and in calories is required to heat at 28.4g( 1 oz) ice cube from -23C TO 1.0C
Tom [10]

1426.58 J  and 340.90 calories heat in joules and in calories is required to heat at 28.4g( 1 oz) ice cube from -23C TO 1.0C.

Explanation:

Data given:

mass = 28.4 gram

initial temperature = -23 degrees

final temperature = 1degress

change in temperature  ΔT = Tfinal - Tinitial

ΔT =  1 -(-23)

 ΔT = 24 degrees

specific heat capacity of ice cube c = 2.093 J/g C

Formula used:

q = mc ΔT

putting the values in the equation:

q= 28.4 x 2.093 x 24

  = 1426.58 J

ENERGY IN CALORIES:

340.90 calories is the energy is required in the process.

3 0
3 years ago
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