We are given:
A rectangular glass pane with
W = 91.1 cm
L = 155.9 cm
We are asked to determine the area of the rectangle. The formula of the area of the rectangle is
A = l x w
A = 91.1 cm x 155.9 cm
A = 14202.49 cm^2<span />
Answer:
acceleration = 22.14 m/s²
time = 2.80 s
Explanation:
given data
initial velocity = 31.0
final velocity =
time = 1.40
solution
we get here acceleration that is
acceleration = 
...............1
acceleration = 
acceleration = 22.14 m/s²
and
by kinematic equation of motion
v = u +at .........2
t = 
time = 2.80 s
Answer:
D. (static equilibrium)
Explanation:
I just took the test and made a 100 with that answer.
From the formula: density=mass/volume
But first, we have to convert the cm³ to m³ by multiplying the value in cm³ by 10^-6, by so doing we'll have the volume to be 0.48*10^-3cm³.
we will also need to convert the mass which is in g to kg by simply dividing by 1000 so the mass becomes 0.12kg
Now we can solve for the density using the formula I earlier stated which is the mass divided by the volume =0.12/0.48*10^-3 so the density will be 0.25*10^3kgm-3 or 2.5*10^2kgm-3
Answer:
See solution below
Explanation:
The standard equation of a wave is represented by: Y = Asin 2π(x/λ – ft)
A is the amplitude
λ is the wavelength
f is the frequency
t is the time
Comparing the standard with the given equation Y = 0.005sin 2π(0.5x – 200t)
i) A = 0.005m
Amplitude is 0.005m
ii) ω = 2πf
ω = 2π(200)
ω = 400π rad/s
iii) ω = 2πf
400π = 2πf
200 = f
Swap
f = 200Hertz
iv) Period = 1/f
Period = 1/200
Period = 0.005secs
v) wave number =
vi) Wavelength λ
0.5x = x/λ
0.5 = 1/λ
λ = 1/0.5
λ = 2m
vii) velocity - fλ
velocity = 200 * 2
velocity = 400m/s
