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Aleksandr-060686 [28]
4 years ago
10

How does density vary with temperature?

Chemistry
2 answers:
agasfer [191]4 years ago
7 0
The cooler something is, the more dense it is because the molecules are closer together when cooler. 
nexus9112 [7]4 years ago
3 0
Things expand when heated. therefore the molecules are farther apartand the matierial is less dense. Things expand because their molecules are vibrating faster and are taking up more space

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Which regions on the periodic table can adopt positive and negative oxidation numbers?
Dennis_Churaev [7]

<span>The region(s) of the periodic table which are made up of elements that can adopt both positive and negative oxidation numbers are the “non-metal” region. As we can see on the periodic table, the elements situated at the right side of the table have two oxidation states, one positive and the other a negative. </span>

7 0
3 years ago
Is the following nuclear equation balanced?<br><br> No<br> Yes
fredd [130]

Answer:

Yes.

The nuclear equation {226/88 Ra → 222/26 Rn + 4/2 He} is balanced. As we know that an alpha particle is identical to a helium atom. This implies that if an alpha particle is eliminated from an atom's nucleus, an atomic number of 2 and a mass number of 4 is lost.

Therefore, the equation will be reduced to:

226 - 4 = 222

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Hence, the equation is balanced.

Explanation:

7 0
3 years ago
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Suppose a snack bar is burned in a calorimeter and heats 2,000 g water by 20 °C. How much heat energy was released? (Hint: Use t
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The answer is: 167360

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3 years ago
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For double-helix formation, DG can be measured to be 2 54 kJ mol 1 ( 2 13 kcal mol 1 ) at pH 7.0 in 1 M NaCl at 25 8C (298 K). T
levacccp [35]

Answer:

ΔS = -661.0J/mol is the entropy change for the system

ΔS = -842J/mol.K is the entropy change for the surroundings

Explanation:

From the relationship between ΔG, T, ΔH and ΔS,

Mathematically, ΔG = ΔH - TΔS

TΔS = ΔH - ΔS

ΔS = ΔH - ΔS / T

but ΔG = -54 kJ/mol, ΔH = -251 kJ/mol and T = 25 °C (298 K)

plugging into the equation,

ΔS = -251 kJ/mol - ( -54 kJ/mol) / 298

ΔS  = -0.6610KJ/mol or in J.mol

ΔS = -661.0J/mol is the entropy change for the system

  • For entropy change for the surroundings = ΔS = ΔH/T
  • ΔS  = -251 kJ/mol / 298K
  • ΔS = -0.84KJ/mol.K or -842J/mol.K is the entropy change for the surroundings
8 0
3 years ago
If this container of gas is heated,
iogann1982 [59]

Answer:

theory

Explanation:

kinetic theory of gases

5 0
3 years ago
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